从数组 Ramda 中按 id 删除对象

Question

我想使用 Ramda 按 id 从数组中删除对象。例如：

const arr = [
  {id: '1', name: 'Armin'},
  {id: '2', name: 'Eren'}, <- delete this object
  {id: '3', name: 'Mikasa'}
];

Answer 1

您可以使用 filter 函数，使用组合函数 propEq & not

const result = filter(
  compose(
   not,
   propEq('id', 2)
  ),
  array,
)
console.log(result)

Answer 2

您可以使用 reject.

The reject() is a complement to the filter(). It excludes elements of a filterable for which the predicate returns true.

let res = R.reject(R.propEq('id', '2'))(arr);

Answer 3

您可以同时使用 filter 或 reject:

R.reject(o => o.id === '2', arr);

R.filter(o => o.id !== '2', arr);

Answer 4

// you could create a generic rejectWhere function
const rejectWhere = (arg, data) => R.reject(R.whereEq(arg), data);


const arr = [
  {id: '1', name: 'Armin'},
  {id: '2', name: 'Eren'}, // <- delete this object
  {id: '3', name: 'Mikasa'}
];


console.log(
  'result', 
  rejectWhere({ id: '2' }, arr),
);

// but also
// rejectWhere({ name: 'Eren' }, arr),

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从数组 Ramda 中按 id 删除对象

Delete object by id from array Ramda

javascript

functional-programming

ramda.js