渲染组件时的 onClick 函数 运行
onClick Function running while Rendering Component
onCLick 处理程序运行 渲染组件时,代码是否有错误?
class MappedEmoji extends React.Component{
render(){
const data = this.props.emoji.map(emoji => {
return(
<span onClick={this.props.handleClick(emoji)} className="myEmoji">{emoji}</span>
)
});
return(
<div> {data}</div>
)
}
}
class StickersComponent extends React.Component{
constructor(props){
super(props);
this.state={
Emoji:["","","","","","","","","","","","","","",""],
};
this.handleClick = this.handleClick.bind(this);
}
handleClick(emoji){
console.log(emoji);
}
render(){
return(
<div className="stickers555">
<div className="_emoji">
{
<MappedEmoji emoji={this.state.Emoji}
handleClick = {this.handleClick}/>
}
</div>
</div>
)
}
}
ReactDOM.render(<StickersComponent />, document.getElementById('App'))
以上是完美呈现所有表情符号的代码,但由于 onclick 处理程序绑定到 onClick 函数,它没有绑定或可能有其他问题。由于点击处理程序是绑定的,我在渲染时在控制台中获取所有表情符号。
尝试回叫。
<span onClick={() => this.props.handleClick(emoji)} className="myEmoji">
如果您必须将参数传递给函数,并且不想立即调用它,则需要使用回调。
onClick={ () => yourFunction(argument1) }
onCLick 处理程序运行 渲染组件时,代码是否有错误?
class MappedEmoji extends React.Component{
render(){
const data = this.props.emoji.map(emoji => {
return(
<span onClick={this.props.handleClick(emoji)} className="myEmoji">{emoji}</span>
)
});
return(
<div> {data}</div>
)
}
}
class StickersComponent extends React.Component{
constructor(props){
super(props);
this.state={
Emoji:["","","","","","","","","","","","","","",""],
};
this.handleClick = this.handleClick.bind(this);
}
handleClick(emoji){
console.log(emoji);
}
render(){
return(
<div className="stickers555">
<div className="_emoji">
{
<MappedEmoji emoji={this.state.Emoji}
handleClick = {this.handleClick}/>
}
</div>
</div>
)
}
}
ReactDOM.render(<StickersComponent />, document.getElementById('App'))
以上是完美呈现所有表情符号的代码,但由于 onclick 处理程序绑定到 onClick 函数,它没有绑定或可能有其他问题。由于点击处理程序是绑定的,我在渲染时在控制台中获取所有表情符号。
尝试回叫。
<span onClick={() => this.props.handleClick(emoji)} className="myEmoji">
如果您必须将参数传递给函数,并且不想立即调用它,则需要使用回调。
onClick={ () => yourFunction(argument1) }