如何重命名子目录中的图像？

Question

我创建了一个用于训练神经网络的合成图像数据集。每个图像文件夹都有一个 "images" 文件夹和一个 "masks" 文件夹。不幸的是，"images" 文件夹中的图像名称不正确。

├── img995
│   ├── images
│   │   └── img142.png
│   └── masks
│       ├── img10_mask10_.png
│       ├── img10_mask10.png

我的目标是重命名 "images" 文件夹中的图像（而不是 masks 文件夹中的图像）。

我试过这段代码，但它没有按预期工作：

import os
os.getcwd()
collection = "/home/dataset/"

for imi in os.listdir(collection):
    for images, masks in imi:
        for p in images:
            os.rename(collection + p + images,
                      collection + p + str(995 + i) + ".png")

Error message:

      4 for imi in os.listdir(collection):
----> 5     for images, masks in imi:
      6         for p in images:
      7             os.rename(collection + p + images,

ValueError: not enough values to unpack (expected 2, got 1)

Answer 1

我对您的要求有点困惑，但是如果您想将 _new 添加到 image 文件夹中的所有图像，您可以使用以下命令：

for root, dirs, files in os.walk('dataset'):
    if os.path.basename(root) == 'images':
        for f in files:
            name, ext = os.path.splitext(f)
            os.rename(os.path.join(root, f), os.path.join(root, name + '_new' + ext))

Answer 2

glob 可以成为你的朋友。基本上，如果你想循环遍历 image 子文件夹下的所有 png 文件，你可以这样做：

import os
import glob

collection = "/home/dataset"

generic_pattern = os.path.join(
    collection,
    "*", "images", "*.png"
)

for a_file in glob.glob(generic_pattern):
    f_path, f_name = os.path.split(a_file)
    f_raw_name, f_ext = f_name.split('.')
    # not sure what you want to do for the new file name
    new_name = f_path.split(os.sep)[-2]  # would be 'img995' in the example
    f_new = os.path.join(
        f_path, 
        '{0}.{1}'.format(new_name, f_ext)
    )
    # to see what you will be doing:
    print(a_file, f_new)
    # if everything works fine, uncomment this:
    # os.rename(a_file, f_new)

Answer 3

import os
os.getcwd()
collection = "/home/dataset/"

for imi in os.listdir(collection): # Lists all files and folders
    path = '{0}{1}'.format(collection, imi)
    if(os.path.isdir(path)): # Filter by folders
        folder_number = imi[3:] # Collect folder number
        image_folder = '{0}/images'.format(path) # Collect image folder
        for image in os.listdir(image_folder): # Collect image in image folder
            image_path = '{0}/{1}'.format(image_folder, image) # Build original image path
            new_image = 'img{0}.png'.format(folder_number) # New image file name
            new_image_path = '{0}/{1}'.format(image_folder, new_image) # Build new image path
            os.rename(image_path, new_image_path) # Rename image with folder number

按照您的示例树结构，这将重命名

├── imgX
│   ├── images
│   │   └── imgY.png    <-- This File 
│   └── masks
│       ├── img10_mask10_.png
│       ├── img10_mask10.png

到

├── imgX
│   ├── images
│   │   └── imgX.png  <-- This File
│   └── masks
│       ├── img10_mask10_.png
│       ├── img10_mask10.png

对于 home/dataset/

中的所有 img 个文件夹

Answer 4

我认为这可以解决您的问题：

import os
first_list = [name for name in os.listdir("/home/dataset/") if name.endswith(".png")]
# if you want to rename and enumerate your images
final = [str(x[0])+'_new_name.png' for x in enumerate(first_list)]

# if you don't want to enumerate and just rename them
final = ['new_name.' + x.split('.')[1] for x in first_list]

祝你好运！

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