表情符号肤色检测

Question

在此 post 之后，我尝试将代码从 Swift 2.0 更新到 Swift 5.0，以检查哪些表情符号有可用的肤色或没有可用的其他变体。我的详细更新代码：

extension String {
var emojiSkinToneModifiers: [String] {
    return [ "", "", "", "", "" ]
}

var emojiVisibleLength: Int {
    var count = 0
    enumerateSubstrings(in: startIndex..<endIndex, options: .byComposedCharacterSequences) { (_, _, _, _) in
        count = count + 1
    }
    return count
}

var emojiUnmodified: String {
    if self.count == 0 {
        return ""
    }
    let range = String(self[..<self.index(self.startIndex, offsetBy: 1)])
    return range
}

var canHaveSkinToneModifier: Bool {
    if self.count == 0 {
        return false
    }
    let modified = self.emojiUnmodified + self.emojiSkinToneModifiers[0]
    return modified.emojiVisibleLength == 1
}
}

并将其与数组一起使用：

let emojis = [ "", "", "" ]
for emoji in emojis {
   if emoji.canHaveSkinToneModifier {
        let unmodified = emoji.emojiUnmodified
        print(emoji)
        for modifier in emoji.emojiSkinToneModifiers {
            print(unmodified + modifier)
        }
    } else {
      print(emoji)
    }
 }

输出：将变体分配给没有或已经存在的表情符号，而不是：

我想 enumerateSubstringsInRange 是不正确的并且 self.characters.count 现在变得 self.count 与 before Swift 4 相比更容易和正确地计算一个表情符号（组合），但在这方面可能没有用案件。我没看错什么？谢谢

Answer 1

A "hack" 将比较正确表情符号（如“”）和 wanna-be 表情符号（如“”）。

我在这里和那里修改了您的代码以使其工作：

extension String {
    static let emojiSkinToneModifiers: [String] =  ["", "", "", "", ""]

    var emojiVisibleLength: Int {
        var count = 0
        let nsstr = self as NSString
        let range = NSRange(location: 0, length: nsstr.length)
        nsstr.enumerateSubstrings(in: range,
                            options: .byComposedCharacterSequences)
        { (_, _, _, _) in

            count = count + 1
        }
        return count
    }

    var emojiUnmodified: String {
        if isEmpty {
            return self
        }
        let string = String(self.unicodeScalars.first!)
        return string
    }

    private static let emojiReferenceSize: CGSize = {
        let size = CGSize(width : CGFloat.greatestFiniteMagnitude,
                          height: CGFloat.greatestFiniteMagnitude)
        let rect = ("" as NSString).boundingRect(with: size,
                                                     options: .usesLineFragmentOrigin,
                                                     context: nil)
        return rect.size
    }()

    var canHaveSkinToneModifier: Bool {
        if isEmpty {
            return false
        }

        let modified = self.emojiUnmodified + String.emojiSkinToneModifiers[0]

        let size = (modified as NSString)
            .boundingRect(with: CGSize(width : CGFloat.greatestFiniteMagnitude,
                                       height: .greatestFiniteMagnitude),
                          options: .usesLineFragmentOrigin,
                          context: nil).size

        return size == String.emojiReferenceSize
    }
}

让我们试试看：

let emojis = [ "", "", "" ]
for emoji in emojis {
    if emoji.canHaveSkinToneModifier {
        let unmodified = emoji.emojiUnmodified
        print(unmodified)
        for modifier in String.emojiSkinToneModifiers {
            print(unmodified + modifier)
        }
    } else {
        print(emoji)
    }
    print("\n")
}

瞧！

表情符号肤色检测

Emoji skin-tone detect

ios

emoji

swift