使用元编程递归初始化 std::array
Recursively initialise std::array using metaprogramming
我必须初始化一个 std::array<my_vector, N>
,my_vector
是一个带有自定义分配器的 std::vector
。我的做法是:
- 已分配
N
个内存池
- 创建了
std::array
个 allocator
,每个都有自己的内存池
- 创建了
std::vector
个 std::array
,每个都有自己的分配器。
简化的代码如下所示:
std::array<std::array<char, POOL_SIZE>, N> memory_pools;
std::array<allocator<POOL_SIZE>, N> allocators{
std::get<0>(memory_pools),
std::get<1>(memory_pools),
std::get<2>(memory_pools),
//...
std::get<N-1>(memory_pools),
};
using my_vector = std::vector<my_class, my_allocator>;
std::array<my_vector, N> vectors{
my_vector{std::get<0>(allocators)},
my_vector{std::get<1>(allocators)},
my_vector{std::get<2>(allocators)},
//...
my_vector{std::get<N-1>(allocators)},
}
这行得通,但是,这是相当冗长的,考虑到我的常量 N
超过 100,并且手工编写所有这些会产生臃肿的代码,并且当我换N了,这一节又得重新写了
问:有没有办法让编译器帮我写初始化?
我想做的是
std::array<allocator<POOL_SIZE>, N> allocators =
make_array_from_pool<POOL_SIZE, N>(memory_pools);
std::array<my_vector, N> vectors =
make_array_from_allocators<N>(allocators);
我已经尝试在嵌套 class 中执行一些递归模板函数,但我遇到了转换错误。
这大致就是我正在尝试的:
template<size_t POOL_SIZE, size_t N, size_t ORDER>
class ArrayMaker{
static std::array<allocator<POOL_SIZE>, ORDER> from_pool(
std::array<std::array<char, POOL_SIZE>, N>
memory_pool
){
return {
ArrayMaker<POOL_SIZE, N, ORDER-1>::from_pool(memory_pool),
std::get<ORDER-1>(memory_pool)
};
}
};
template<size_t POOL_SIZE, size_t N>
class ArrayMaker<POOL_SIZE, N, 1>{
static std::array<allocator<POOL_SIZE>, 1> from_pool(
std::array<std::array<char, POOL_SIZE>, N>
memory_pool
){
return {std::get<0>(memory_pool)};
}
};
template<size_t POOL_SIZE, size_t N>
static std::array<allocator<POOL_SIZE>, N> make_array_from_pool(
std::array<std::array<char, POOL_SIZE>, N>
memory_pool
){
return ArrayMaker<POOL_SIZE,N, N>::from_pool(memory_pool);
}
我得到的错误是could not convert ... from '<brace-enclosed initializer list>' to 'std::array<allocator<POOL_SIZE>, 2>'
我的理解是因为std::array只支持聚合初始化
你不需要任何递归来实现这个,你可以简单地使用 std::index_sequence
。例如
template <std::size_t... Is>
void init_arrays_impl(std::index_sequence<Is...>)
{
static constexpr auto N = sizeof...(Is);
std::array<std::array<char, POOL_SIZE>, N> memory_pools;
std::array<allocator<POOL_SIZE>, N> allocators{
std::get<Is>(memory_pools)...
};
using my_vector = std::vector<my_class, my_allocator>;
std::array<my_vector, N> vectors{
my_vector{std::get<Is>(allocators)}...
};
}
template <std::size_t N>
void init_arrays()
{
init_arrays_impl(std::make_index_sequence<N>{});
}
我必须初始化一个 std::array<my_vector, N>
,my_vector
是一个带有自定义分配器的 std::vector
。我的做法是:
- 已分配
N
个内存池 - 创建了
std::array
个allocator
,每个都有自己的内存池 - 创建了
std::vector
个std::array
,每个都有自己的分配器。
简化的代码如下所示:
std::array<std::array<char, POOL_SIZE>, N> memory_pools;
std::array<allocator<POOL_SIZE>, N> allocators{
std::get<0>(memory_pools),
std::get<1>(memory_pools),
std::get<2>(memory_pools),
//...
std::get<N-1>(memory_pools),
};
using my_vector = std::vector<my_class, my_allocator>;
std::array<my_vector, N> vectors{
my_vector{std::get<0>(allocators)},
my_vector{std::get<1>(allocators)},
my_vector{std::get<2>(allocators)},
//...
my_vector{std::get<N-1>(allocators)},
}
这行得通,但是,这是相当冗长的,考虑到我的常量 N
超过 100,并且手工编写所有这些会产生臃肿的代码,并且当我换N了,这一节又得重新写了
问:有没有办法让编译器帮我写初始化?
我想做的是
std::array<allocator<POOL_SIZE>, N> allocators =
make_array_from_pool<POOL_SIZE, N>(memory_pools);
std::array<my_vector, N> vectors =
make_array_from_allocators<N>(allocators);
我已经尝试在嵌套 class 中执行一些递归模板函数,但我遇到了转换错误。
这大致就是我正在尝试的:
template<size_t POOL_SIZE, size_t N, size_t ORDER>
class ArrayMaker{
static std::array<allocator<POOL_SIZE>, ORDER> from_pool(
std::array<std::array<char, POOL_SIZE>, N>
memory_pool
){
return {
ArrayMaker<POOL_SIZE, N, ORDER-1>::from_pool(memory_pool),
std::get<ORDER-1>(memory_pool)
};
}
};
template<size_t POOL_SIZE, size_t N>
class ArrayMaker<POOL_SIZE, N, 1>{
static std::array<allocator<POOL_SIZE>, 1> from_pool(
std::array<std::array<char, POOL_SIZE>, N>
memory_pool
){
return {std::get<0>(memory_pool)};
}
};
template<size_t POOL_SIZE, size_t N>
static std::array<allocator<POOL_SIZE>, N> make_array_from_pool(
std::array<std::array<char, POOL_SIZE>, N>
memory_pool
){
return ArrayMaker<POOL_SIZE,N, N>::from_pool(memory_pool);
}
我得到的错误是could not convert ... from '<brace-enclosed initializer list>' to 'std::array<allocator<POOL_SIZE>, 2>'
我的理解是因为std::array只支持聚合初始化
你不需要任何递归来实现这个,你可以简单地使用 std::index_sequence
。例如
template <std::size_t... Is>
void init_arrays_impl(std::index_sequence<Is...>)
{
static constexpr auto N = sizeof...(Is);
std::array<std::array<char, POOL_SIZE>, N> memory_pools;
std::array<allocator<POOL_SIZE>, N> allocators{
std::get<Is>(memory_pools)...
};
using my_vector = std::vector<my_class, my_allocator>;
std::array<my_vector, N> vectors{
my_vector{std::get<Is>(allocators)}...
};
}
template <std::size_t N>
void init_arrays()
{
init_arrays_impl(std::make_index_sequence<N>{});
}