str_replace_all Error: `replacement` must be a character vector

Question

替换混合向量中模式的最简单方法是什么？

vec <- c(0, 2500, "A", "B", 2, 3, "M", "+", "\"\"")

library(stringr)

vec <- str_replace_all(vec, c("A" = 0, "B" = 9, "M" = 6, "+" = 0, "\"\"" = 0))

Error: `replacement` must be a character vector

期待这个矢量：

[1]“0”“2500”“0”“9”“2”“3”“6”“0”“0”

Answer 1

在替换中使用引号，因为 str_replace_all 需要一个字符串作为替换：

vec <- str_replace_all(vec, c("A" = "0", "B" = "9", "M" = "6", "+" = "0", "\"\"" = "0"))

str_replace_all Error: `replacement` must be a character vector

str_replace_all Error: `replacement` must be a character vector

r

str-replace

stringr