C# 反序列化 json 并查找

Question

如何在此列表中找到特定的 ID？

var contactList = JsonConvert.DeserializeObject<ContactList>(jsonString);

contactList.contacts.FindAll(x => x.id == item.id);

上面的代码没有按 id 过滤，而是从对象返回所有行。

(Visual Studio 没有显示 .Where 子句只有 .Find 和 .FindAll)

C#代码

namespace RestDemo.Model 
{ 
   public class Phone 
   { 
      public string mobile { get; set; } 
      public string home { get; set; } 
      public string office { get; set; } 
   } 

   public class Contact 
   { 
      public int id { get; set; } 
      public string name { get; set; } 
      public string email { get; set; } 
      public string address { get; set; } 
      public string gender { get; set; } 
      public Phone phone { get; set; } 
   } 

   public class ContactList 
   { 
      public List<Contact> contacts { get; set; } 
   } 
}

Json:

{ "contacts": [     {           "id": 200,          "name": "Ravi Tamada",          "email": "ravi@gmail.com",          "address": "xx-xx-xxxx,x - street, x - country",            "gender": "male",           "phone": {              "mobile": "+91 0000000000",             "home": "00 000000",                "office": "00 000000"           }       },      {           "id": 201,          "name": "Klev Krist",           "email": "klev@gmail.com",          "address": "xx-xx-xxxx,x - street, x - country",            "gender": "male",           "phone": {              "mobile": "+91 0000000000",             "home": "00 000000",                "office": "00 000000"           }       },      {           "id": 202,          "name": "Paul Neil",            "email": "paul.neil@gmail.com",         "address": "xx-xx-xxxx,x - street, x - country",            "gender": "male",           "phone": {              "mobile": "+91 0000000000",             "home": "00 000000",                "office": "00 000000"           }       }   ]}

谢谢

Answer 1

假设您要查找某个 id，我们将调用它

var idToFind = "myID";

要查找具有所述 ID 的所有联系人：

var contacts = contactList.contacts.Where(contact=> contact.id == idToFind);

要查找至少一位具有上述 ID 的联系人：

var contactWithID = contactList.contacts.FirstOrDefault(contact=> contact.id == idToFind);
// Before using, check if null, means no contact matched the id.
if(contactWithID != null)
{
   // A contact was found.
}
else
{
   // No contact matching that id is found.
}

Answer 2

根据你对@Tenretni 的回答的评论，我猜你错过了在你的代码中使用 System.Linq 库。

在您的代码中导入 System.Collections.Generic 和 System.Linq 并使用 FirstOrDefault() 或 .Where() 子句

using System.Collections.Generic;
using System.Linq;

//…

string jsonString = @"{ 'contacts': [{ 'id': 'c200', 'name': 'Ravi Tamada', 'email': 'ravi@gmail.com', 'address': 'xx-xx-xxxx,x - street, x - country', 'gender': 'male', 'phone': { 'mobile': '+91 0000000000', 'home': '00 000000', 'office': '00 000000' } }] }";

var contactList = JsonConvert.DeserializeObject<ContactList>(jsonString);
var item = "c200";
var result = contactList.contacts.FirstOrDefault(x => x.id == item);
Console.WriteLine(result.name);

//If you have multiple records with same ID then you can try where clause
var result = contactList.contacts.Where(x => x.id == item);      //Here result will be list of Contact

.Net Fiddle

Answer 3

FindAll 方法未将对象分配给搜索结果。

您必须将搜索结果保存在某个地方。

示例多结果

如果您期待多个结果

var contactList = JsonConvert.DeserializeObject<ContactList>(jsonString);
var findedContact = contactList.contacts.FindAll(x => x.id == item.id);
//You business codes..

单个结果示例

如果您只等待 1 个结果

var contactList = JsonConvert.DeserializeObject<ContactList>(jsonString);
var oneContact = contactList.contacts.Find(x => x.id == item.id);
if(oneContact ==null){
    //not found business codes
}
else {
   //find result business codes
}

Answer 4

针对您的情况，我使用相同的 Model 结构反序列化您的 JSON，然后使用 Where linq 子句来实现您的要求。可以在以下位置找到有效的 fiddle：https://dotnetfiddle.net/SAcFja

代码：

using System;
using Newtonsoft.Json;
using System.Collections.Generic;
using System.Linq;

public class Program
{
    public static void Main()
    {
        var jsonString = @"{ 'contacts': [{ 'id': 200, 'name': 'Ravi Tamada', 'email': 'ravi@gmail.com', 'address': 'xx-xx-xxxx,x - street, x - country', 'gender': 'male', 'phone': { 'mobile': '+91 0000000000', 'home': '00 000000', 'office': '00 000000' } }] }";
        var data= JsonConvert.DeserializeObject<ContactList>(jsonString);
        //Console.WriteLine(data.contacts);

        var found=data.contacts.Where(x=>x.id.ToString()=="200");

        foreach(var value in found)
        {
          Console.WriteLine(value.id);
          Console.WriteLine(value.address);     
        }       
    }
}

   public class Phone 
   { 
      public string mobile { get; set; } 
      public string home { get; set; } 
      public string office { get; set; } 
   } 

   public class Contact 
   { 
      public string id { get; set; } 
      public string name { get; set; } 
      public string email { get; set; } 
      public string address { get; set; } 
      public string gender { get; set; } 
      public Phone phone { get; set; } 
   } 

   public class ContactList 
   { 
      public List<Contact> contacts { get; set; } 
   }

id=200时输出：

200
xx-xx-xxxx,x - street, x - country

C# 反序列化 json 并查找

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