对对象字典进行排名的最佳方法是什么？

Question

鉴于以下类：

class Comparison():

    def __init__(self, value):
        self.value = value
        self.rank = 0

class Comparisons(dict):

    def __init__(self):
        super(Comparisons, self).__init__()

    def rank(self):
        # Method to examine each Comparison instance and
        # assign Comparison.rank based on Comparison.value

rank() 方法检查对象并分配等级的有效方法是什么？例如：

comparisons = Comparisons()

# store some Comparison instances
comparisons['one'] = Comparison(10)
comparisons['two'] = Comparison(5)
comparisons['three'] = Comparison(1)

# function to rank the comparisons
comparisons.rank()

print(comparisons['one'].rank)
print(comparisons['two'].rank)
print(comparisons['three'].rank)

Returns:

3
2
1

如果 rank() 方法可以处理平局，那就更好了。

Answer 1

这看起来是最直观（幼稚？）的方式：

def rank(self):
    sorted_comparisons = sorted(self.values(), key=lambda c: c.value)
    for rank, comparison in enumerate(sorted_comparisons, 1):
        comparison.rank = rank

对对象字典进行排名的最佳方法是什么？

What is the best approach to rank a dictionary of objects?

python

sorting

rank