不接受 Twitter Tweep API 中的关键字参数 'user'

Question

我遇到了 api.send.direct.message 代码的问题。
它正在抛出一个 error; peError: send_direct_message() 得到了一个意外的关键字参数 'user'。
我尝试了多种选择，包括 screen_name = user.screen_name 但没有成功。

import tweepy
import time

# Authenticate to Twitter
auth = tweepy.OAuthHandler("Kr2pjbeG3hDC2", 
"3nunhSaUZ9MeAHpmbEhuEEqSFmj2l2EfaMIzxu9")
auth.set_access_token("107550621-n7OrqgFx", 
"mse3r98sEfziOO95qPCrnD0kUh9lJToxRJ3E0Uzmg")

api = tweepy.API(auth, wait_on_rate_limit=True, wait_on_rate_limit_notify=True)

for user in api.followers():
   text="""Hi"""       

   try:
      api.send_direct_message(user=user, text=text) 
      print(user.screen_name)
   except tweepy.TweepError as e:
       print(e.args[0][0]['code'])  # prints 34
      print(e.args[0][0]['message'])
      continue
   except StopIteration:
      break

Answer 1

根据documentation，您应该指定收件人的ID：

API.send_direct_message(recipient_id, text[, quick_reply_type][, attachment_type][, attachment_media_id])

您的代码应该如下所示：

import tweepy
import time

# Authenticate to Twitter
auth = tweepy.OAuthHandler("Kr2pjbeG3hDC2", 
"3nunhSaUZ9MeAHpmbEhuEEqSFmj2l2EfaMIzxu9")
auth.set_access_token("107550621-n7OrqgFx", 
"mse3r98sEfziOO95qPCrnD0kUh9lJToxRJ3E0Uzmg")

api = tweepy.API(auth, wait_on_rate_limit=True, wait_on_rate_limit_notify=True)

for user in api.followers():
   text="""Hi"""       

   try:
      api.send_direct_message(recipient_id=user.id, text=text) 
      print(user.screen_name)
   except tweepy.TweepError as e:
       print(e.args[0][0]['code'])  # prints 34
      print(e.args[0][0]['message'])
      continue
   except StopIteration:
      break

不接受 Twitter Tweep API 中的关键字参数 'user'

Not accepting keyword argument 'user' in Twitter Tweep API

python

tweepy