在 qml 和 python 中选择源的菜单

Question

我必须在 QML 中创建一个菜单，其中包含目录中的项目列表，通过单击其中一个，它会播放视频 (player.play())

这是我尝试过的方法，但不起作用

___.qml

Menu {
    id: menu
    contentItem: ListView {
        model: ui.textMenu
    }
}
Menu {
    id: menu
    y: -200 
    x: 100
    Repeater{
        model: ui.textMenu
        MenuItem {
            text: textMenu.entry
            onClicked:{
                player.source = textMenu.address
                player.play()
            }
        } //x: model.x*(videoPlayer.width - 10)
    }
}

___.py

self.__textMenu = QStandardItemModel(self)
 menuRoles = {entryRole: b"entry", addressRole: b"address"}
 self.__textMenu.setItemRoleNames(menuRoles)

 def menu(self):
    directoryPath = os.path.join(self.__currentPath, r"video" )
    entries = os.listdir(directoryPath) 
    for entry in entries:
        menuVoice = QStandardItem()
        menuVoice.setData(entry, entryRole)
        videoPath = os.path.join(directoryPath, entry)
        menuVoice.setData(videoPath, addressRole)

Answer 1

您的QML似乎与您想要的不一致。在这种情况下，我在 MenuBar 中创建了一个 Menu，其中将使用模型和 Repeater 创建 MenuItem：

import os
import sys

from PySide2 import QtCore, QtGui, QtQml

NameRole = QtCore.Qt.UserRole + 1000
PathRole = QtCore.Qt.UserRole + 1001


def create_model(dir_path):
    model = QtGui.QStandardItemModel()
    roles = {NameRole: b"name", PathRole: b"path"}
    model.setItemRoleNames(roles)
    for name in os.listdir(dir_path):
        it = QtGui.QStandardItem()
        it.setData(name, NameRole)
        it.setData(os.path.join(dir_path, name), PathRole)
        model.appendRow(it)
    return model


def main(args):
    app = QtGui.QGuiApplication(args)

    current_dir = os.path.dirname(os.path.realpath(__file__))
    video_dir = os.path.join(current_dir, "video")
    model = create_model(video_dir)

    engine = QtQml.QQmlApplicationEngine()
    engine.rootContext().setContextProperty("video_model", model)
    current_dir = os.path.dirname(os.path.realpath(__file__))
    filename = os.path.join(current_dir, "main.qml")
    engine.load(QtCore.QUrl.fromLocalFile(filename))
    if not engine.rootObjects():
        return -1
    ret = app.exec_()
    return ret


if __name__ == "__main__":
    sys.exit(main(sys.argv))

import QtQuick 2.13
import QtQuick.Controls 2.13
import QtMultimedia 5.13

ApplicationWindow {
    id: root
    width: 640
    height: 480
    visible: true

    menuBar: MenuBar {
        Menu {
            id: plugins_menu
            title: qsTr("&Videos")
            Repeater{
                model: video_model
                MenuItem{
                    text: model.name
                    onTriggered: {
                        video.source = Qt.resolvedUrl(model.path)
                        video.play()
                    }
                }
            }
        }
    }
    Video {
        id: video
        anchors.fill: parent
    }
}

在 qml 和 python 中选择源的菜单

menu selecting a source in qml and python

python

qt

qml

pyside2