我试图在另一个准备好的声明中包含一个准备好的声明

Question

在这个给定的准备好的语句中，它获取文章标题。当它获得文章标题时，它还应该将该变量发送到另一个准备好的语句中，该语句然后找到给定文章的浏览量。

<table class="table table-colored table-centered table-inverse m-0">
<thead>
<tr>

<th>Title</th>
<th>Category</th>
<th>Writer</th>
<th>Action</th>
<th>Views</th>
</tr>
</thead>
<tbody>


<?php
$stmt = $con -> prepare('select tblposts.id as postid,tblposts.PostTitle as title,tblposts.PostUrl as postname, tblcategory.CategoryName as category,tblwritter.Writter as writter from tblposts left join tblcategory on tblcategory.id=tblposts.CategoryId left join tblwritter on tblwritter.WritterId=tblposts.WritterId where tblposts.Is_Active=?');
$cnt=1;
$stmt -> bind_param('i', $cnt);
$stmt -> execute();
$stmt -> store_result();
$stmt -> bind_result($postid,$title,$postname,$category,$writter);
?>

 <tr>
<?php while ($stmt->fetch()){?>
<td><b><?php echo $postname;?></b></td>
<td><?php echo $category?></td>
<td><?php echo $writter?></td>


<td>
<a href="edit-post.php?pid=<?php echo $postid;?>"><i class="fa fa-pencil" style="color: #29b6f6;"></i></a>
    &nbsp;<a href="manage-posts.php?pid=<?php echo$postid;?>&&action=del" onclick="return confirm('Do you reaaly want to delete ?')"> <i class="fa fa-trash-o" style="color: #f05050"></i></a>
</td>

<?php
$stmt = $con -> prepare('select COUNT(ip) FROM tblviews WHERE postname = ?');
$stmt -> bind_param('s', $postname);
$stmt -> execute();
$stmt -> store_result();
$stmt -> bind_result($ip);
?>
<?php while ($stmt->fetch()){?>
<td><?php echo $ip ?></td>
<?php } ?>

 </tr>


<?php }?>
                                            </tbody>
                                        </table>

此代码的预期结果是将邮寄名发送到准备好的语句中，然后调用任何给定文章中的浏览量。

Answer 1

简短回答：您在循环内覆盖了 $stmt。

长答案，有提示：这可以通过首先编写所有 php，然后最后发出 html（仅使用 php 进行迭代和变量替换）来避免（或至少更容易检测）。

更好的方法是将数据库访问和业务逻辑放入单独的类（即模型）中，并让您的视图向模型（或控制器，取决于您对 MVC 的解释）询问数据需要。

我没有办法测试它，但你应该可以使用一个查询：

select 
    tblposts.id as postid,
    tblposts.PostTitle as title,
    tblposts.PostUrl as postname,
    tblcategory.CategoryName as category,
    tblwritter.Writter as writter,
    COUNT(tblwritter.ip) as views
from tblposts
    left join tblcategory on tblcategory.id=tblposts.CategoryId 
    left join tblwritter on tblwritter.WritterId=tblposts.WritterId 
    left join tblviews on tblviews.postname = tblposts.PostUrl'
where tblposts.Is_Active=?
group by tblposts.PostUrl, tblposts.id, tblposts.PostTitle, tblCategory.CategoryName, tblwritter.Writter

（请注意，MySQL 可能会让您仅在组中命名 tblposts.PostUrl 即可）

这样，您的页面可以简化为如下所示：

<?php
    // do your query here
?>
<table class="table table-colored table-centered table-inverse m-0">
  <thead>
    <tr>

      <th>Title</th>
      <th>Category</th>
      <th>Writer</th>
      <th>Action</th>
      <th>Views</th>
    </tr>
  </thead>
  <tbody>
    <?php while ($stmt->fetch()): ?>
    <tr>
      <td><b><?= $postname ?></b></td>
      <td><?= $category ?></td>
      <td><?= $writter?></td>
      <td>
        <a href="edit-post.php?pid=<?= $postid?>"><i class="fa fa-pencil" style="color: #29b6f6;"></i></a>
&nbsp;<a href="manage-posts.php?pid=<?=$postid?>&&action=del" onclick="return confirm('Do you reaaly want to delete ?')"> <i class="fa fa-trash-o" style="color: #f05050"></i></a>
      </td>
      <td><?= $views ?></td>
    </tr>
    <?php endwhile; ?>
  </tbody>
</table>

我试图在另一个准备好的声明中包含一个准备好的声明

I am trying to include a prepared statement within another prepared statement

html

php

mysql

mysqli

prepared-statement