数组的统计

Question

我需要一个程序来评估任意数量整数的最小值、最大值、平均值和几何平均值。到目前为止，这是我想出的。在我添加 Avg 之前，Min 和 Max 工作得很好。现在 Min 和 Avg 工作正常，但 Max 给出了错误的数字（通常是第二大数字）。几何平均也只给出 0.00000。谢谢你的帮助。

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main(int argc, char const *argv[]) {

  int arr[100], max, i, min, size, lok = 1;
  float arit = 0, geom = 0, sum = 0, prod = 0;
    printf("\nSay how many integers you want to input: ");
    scanf("%d", &size);

    printf("\nType %d integers: ", size);

      for (i = 0; i < size; i++) //put values in arr
        scanf("%d", &arr[i]);
            max = arr[0];
            min = arr[0];
      for (i = 1; i < size; i++) { //calc maximum
        if (arr[i]>max) {
            max = arr[i];
            lok = i+1;
          }


        if (arr[i]<min) { //calc minimum
            min = arr[i];
            lok = i+1;
          }



      for (i = 0; i < size; i++) { //calc avg
            sum = sum + arr[i];
        }
            arit = sum/size;

      for (i = 0; i < size; i++) {
        prod = prod * arr[i];
      }
        geom = pow(prod, 1./size);
      }


      printf("\n%d is maximum", max);
      printf("\n%d is minimum", min);
      printf("\n%f is avg", arit);
      printf("\n%f is geometric avg", geom);




  return 0;
}

Answer 1

这将解决您的 Min 和 Max 问题，我想也将解决几何平均值（检查它）这是一个关闭句子的问题

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main(int argc, char const *argv[]) {

  int arr[100], max, i, min, size, lok = 1;
  float arit = 0, geom = 0, sum = 0, prod = 1;
  printf("\nSay how many integers you want to input: ");
  scanf("%d", &size);

  printf("\nType %d integers: ", size);

  for (i = 0; i < size; i++) //put values in arr
    scanf("%d", &arr[i]);
  max = arr[0];
  min = arr[0];
  for (i = 1; i < size; i++) { //calc maximum
    if (arr[i]>max) {
      max = arr[i];
      lok = i+1;
    }

    if (arr[i]<min) { //calc minimum
      min = arr[i];
      lok = i+1;
    }
  }
  for (i = 0; i < size; i++) { //calc avg
    sum = sum + arr[i];
  }
  arit = sum/size;

  for (i = 0; i < size; i++) {
    prod = prod * arr[i];
  }
  geom = pow(prod, 1./size);

  printf("\n%d is maximum", max);
  printf("\n%d is minimum", min);
  printf("\n%f is avg", arit);
  printf("\n%f is geometric avg", geom);

  return 0;
}

关于几何意味着你正在做这个。

float arit = 0, geom = 0, sum = 0, prod = 0;

然后

  for (i = 0; i < size; i++) {
    prod = prod * arr[i];
  }

那总是 return 0 因为你将 prod 初始化为 0

Answer 2

两个主要问题是

错位的右 } 大括号
prod = 0

我也做了一些其他的改变：

检查输入的有效性
使用 double 而不是 float（除非有充分的理由不这样做）。
删除不用的lok
所有统计只需要一个循环
按照惯例移动了 \n 换行符的位置。

这是修改后的代码：

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main(int argc, char const *argv[]) {

    int arr[100], max, i, min, size;
    double arit = 0, geom = 0, sum = 0, prod = 1;   // init prod to 1

    printf("\nSay how many integers you want to input: ");
    if(scanf("%d", &size) != 1 || size < 1 || size > 100) {
        exit(1);                                    // or other action
    }

    printf("\nType %d integers:\n", size);          // added newline
    for (i = 0; i < size; i++) {
        if(scanf("%d", &arr[i]) != 1) {
            exit(1);                                // or other action
        }
    }

    max = arr[0];
    min = arr[0];

    for (i = 0; i < size; i++) {                    // just one loop
        if (arr[i] > max) {
            max = arr[i];
        }
        if (arr[i] < min) {
            min = arr[i];
        }
        sum = sum + arr[i];
        prod = prod * arr[i];
    }

    arit = sum / size;
    geom = pow(prod, 1.0 / size);

    printf("%d is maximum\n", max);                 // reposition newlines
    printf("%d is minimum\n", min);
    printf("%f is avg\n", arit);
    printf("%f is geometric avg\n", geom);
    return 0;
}

数组的统计

Statistics of an array

c

arrays

average

max

min