通过引用另一个数组从数组中删除对象

Question

我有一个名为 new_svrgrp_member 的数组，就像这样 -

new_svrgrp_member = [];
new_svrgrp_member.push({
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN001271"
},{
    Member:"m82298s2", MemberClass:"user", Parent:"SVR_ADM_WN001271"
},{
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN000868"
},{
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN000901"
},{
    Member:"v38250s", MemberClass:"user", Parent:"SVR_ADM_WN000903"
},{
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN002085"
},{
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN001367"
},{
    Member:"v38250s", MemberClass:"user", Parent:"SVR_ADM_WN001367"
},{
    Member:"d76686g2", MemberClass:"user", Parent:"SVR_ADM_WNR00096"
},{
    Member:"s98681s2", MemberClass:"user", Parent:"SVR_ADM_WGR00006"
})

然后我有一个像这样的 FilterMmbr 数组 -

FilterMmbr = [];
FilterMmbr.push({Name: "s98681s2"},{Name: "s98681s"},{Name: "v38250s"},{Name: "SI_VWAdmChk"})

我需要从 new_svrgrp_member 中取出所有匹配 FilterMmbr's Name 属性和 new_svrgrp_member's Member [=33= 的对象].

我使用了以下代码来做到这一点 -

for each(Mmbr in FilterMmbr)
{
    var removeIndex = new_svrgrp_member.map(function (item) {
        return item.Member;
    }).indexOf(Mmbr.Name);
    ~removeIndex && new_svrgrp_member.splice(removeIndex, 1);
}

它删除了对象但只有一个匹配项，这是我得到的输出 -

[INFO] New members after filtering...
[INFO] Member:a25346j2 MemberClass:user Parent:SVR_ADM_WN001271
[INFO] Member:m82298s2 MemberClass:user Parent:SVR_ADM_WN001271
[INFO] Member:a25346j2 MemberClass:user Parent:SVR_ADM_WN000868
[INFO] Member:a25346j2 MemberClass:user Parent:SVR_ADM_WN000901
[INFO] Member:a25346j2 MemberClass:user Parent:SVR_ADM_WN002085
[INFO] Member:a25346j2 MemberClass:user Parent:SVR_ADM_WN001367
[INFO] Member:v38250s MemberClass:user Parent:SVR_ADM_WN001367  //Still exists
[INFO] Member:d76686g2 MemberClass:user Parent:SVR_ADM_WNR00096

如何删除所有匹配的对象，为什么还剩下一个对象？

Answer 1

您可以使用 Array.filter to strip values out of new_svrgrp_member that match a name in FilterMmbr (found using Array.some):

let new_svrgrp_member = [];
new_svrgrp_member.push({
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN001271"
},{
    Member:"m82298s2", MemberClass:"user", Parent:"SVR_ADM_WN001271"
},{
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN000868"
},{
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN000901"
},{
    Member:"v38250s", MemberClass:"user", Parent:"SVR_ADM_WN000903"
},{
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN002085"
},{
    Member:"a25346j2", MemberClass:"user", Parent:"SVR_ADM_WN001367"
},{
    Member:"v38250s", MemberClass:"user", Parent:"SVR_ADM_WN001367"
},{
    Member:"d76686g2", MemberClass:"user", Parent:"SVR_ADM_WNR00096"
},{
    Member:"s98681s2", MemberClass:"user", Parent:"SVR_ADM_WGR00006"
});

let FilterMmbr = [];
FilterMmbr.push({Name: "s98681s2"},{Name: "s98681s"},{Name: "v38250s"},{Name: "SI_VWAdmChk"});

new_svrgrp_member = new_svrgrp_member.filter(m => !FilterMmbr.some(f => f.Name == m.Member));
console.log(new_svrgrp_member);

通过引用另一个数组从数组中删除对象

Remove objects from array by referencing another aray

javascript

ecmascript-5