Phaser 3 示例文本输入无法检测到键入的 Z 键？

Question

此代码在键入时无法检测到字母 "Z"。我从 Phaser 3 Examples - Text Entry.

得到的

var config = {
    type: Phaser.AUTO,
    parent: 'phaser-example',
    width: 800,
    height: 600,
    scene: {
        create: create,
        update: update
    }
};

var keySpace;
var keyBackspace;
var textEntry;

var game = new Phaser.Game(config);

function create ()
{
    this.add.text(10, 10, 'Enter your name:', { font: '32px Courier', fill: '#ffffff' });

    textEntry = this.add.text(10, 50, '', { font: '32px Courier', fill: '#ffff00' });

    // keys = this.input.keyboard.addKeys('A,B,C');

    keySpace = this.input.keyboard.addKey(Phaser.Input.Keyboard.KeyCodes.SPACE);
    keyBackspace = this.input.keyboard.addKey(Phaser.Input.Keyboard.KeyCodes.BACKSPACE);

    this.input.keyboard.on('keydown', function (event) {

        if (event.keyCode === 8 && textEntry.text.length > 0)
        {
            textEntry.text = textEntry.text.substr(0, textEntry.text.length - 1);
        }
        else if (event.keyCode === 32 || (event.keyCode >= 48 && event.keyCode < 90))
        {
            textEntry.text += event.key;
        }

        console.log(event);
    });
}

function update ()
{
}

我设法添加了这段代码来做一些很好的事情。我正在尝试捕获键入它的键盘并将其注册到自定义 UI 上。如果他或她键入 "Captain Zulu"，代码将不起作用，这只会注册 "Captain ulu"，因为它没有检测到它。如果他们输入 "Zuzuki" 也会出现 "uuki" 而不是。

 else if (event.keyCode === 38 )
 {
     dosomethingthirtyeight();
     showPanel();
 }
 else if (event.keyCode === 40 )
 {
     dosomethingfortyeight();
     showPanel();
 }

Answer 1

这解决了问题。我在这里找到了键码 https://github.com/photonstorm/phaser/blob/v3.20.0/src/input/keyboard/keys/KeyCodes.js#L764

(event.keyCode === 190 || event.keyCode === 90) // the period isnt working too
{
  textEntry.text += event.key;
}

Phaser 3 示例文本输入无法检测到键入的 Z 键？

Phaser 3 Examples Text Entry cant detect Z key typed?

phaser-framework