sqlsrv_query() 需要参数 1
sqlsrv_query() expects parameter 1
我正在尝试 运行 以下查询。
SELECT
min(rd.region) AS region,
min(ri.ri_id) AS ri_id,
ri.service_date,
min(ri.tt_route_start_time) AS tt_route_start_time,
min(ri.tt_route_end_time) AS tt_route_end_time,
min(ri.tgqh_exit_time) AS tgqh_exit_time,
min(ri.violation_vehicle_details) AS violation_vehicle_details,
min(ri.tt_sop_violation_start_route) AS tt_sop_violation_start_route,
min(ri.crew_violation_details) AS crew_violation_details,
rd.route_name,
vd.v_no,
min(ri.vehicle_violation_justify) AS vehicle_violation_justify,
min(ri.crew_violation_justify) AS crew_violation_justify,
min(ri.start_time_violation_justify) AS start_time_violation_justify,
min(ri.v_justification) AS v_justification,
min(ri.c_justification) AS c_justification,
min(ri.st_justification) AS st_justification,
min(vd.v_type) AS v_type
FROM vehicles3.ride_details AS ri
INNER JOIN vehicles3.route_details AS rd ON ri.route_id = rd.r_id
INNER JOIN vehicles3.vehicle_details AS vd ON vd.v_id = ri.v_id
WHERE
ri.status = 1 AND
rd.r_id = '93'AND
ri.service_date = '2019-10-14'
GROUP BY ri.service_date, rd.route_name, vd.v_no, rd.r_id
ORDER BY ri.service_date, rd.route_name, vd.v_no, rd.r_id
但是当我运行它显示以下错误:
Warning: sqlsrv_query() expects parameter 1 to be resource,
Warning: sqlsrv_num_rows() expects parameter 1 to be resource
但是,当我回显 运行 查询并在 SQL 服务器中 运行 它时,它工作得很好。
expects parameter 1 to be resource
表示您正在向该函数传递 null
资源,可能是因为与数据库的连接失败。
关于 sqlsrv_num_rows
错误的相同问题。
您必须在执行查询之前检查连接状态。
$serverName = "serverName\sqlexpress";
$connectionInfo = array( "Database"=>"dbName", "UID"=>"username", "PWD"=>"password" );
$conn = sqlsrv_connect( $serverName, $connectionInfo);
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}
我正在尝试 运行 以下查询。
SELECT
min(rd.region) AS region,
min(ri.ri_id) AS ri_id,
ri.service_date,
min(ri.tt_route_start_time) AS tt_route_start_time,
min(ri.tt_route_end_time) AS tt_route_end_time,
min(ri.tgqh_exit_time) AS tgqh_exit_time,
min(ri.violation_vehicle_details) AS violation_vehicle_details,
min(ri.tt_sop_violation_start_route) AS tt_sop_violation_start_route,
min(ri.crew_violation_details) AS crew_violation_details,
rd.route_name,
vd.v_no,
min(ri.vehicle_violation_justify) AS vehicle_violation_justify,
min(ri.crew_violation_justify) AS crew_violation_justify,
min(ri.start_time_violation_justify) AS start_time_violation_justify,
min(ri.v_justification) AS v_justification,
min(ri.c_justification) AS c_justification,
min(ri.st_justification) AS st_justification,
min(vd.v_type) AS v_type
FROM vehicles3.ride_details AS ri
INNER JOIN vehicles3.route_details AS rd ON ri.route_id = rd.r_id
INNER JOIN vehicles3.vehicle_details AS vd ON vd.v_id = ri.v_id
WHERE
ri.status = 1 AND
rd.r_id = '93'AND
ri.service_date = '2019-10-14'
GROUP BY ri.service_date, rd.route_name, vd.v_no, rd.r_id
ORDER BY ri.service_date, rd.route_name, vd.v_no, rd.r_id
但是当我运行它显示以下错误:
Warning: sqlsrv_query() expects parameter 1 to be resource,
Warning: sqlsrv_num_rows() expects parameter 1 to be resource
但是,当我回显 运行 查询并在 SQL 服务器中 运行 它时,它工作得很好。
expects parameter 1 to be resource
表示您正在向该函数传递 null
资源,可能是因为与数据库的连接失败。
关于 sqlsrv_num_rows
错误的相同问题。
您必须在执行查询之前检查连接状态。
$serverName = "serverName\sqlexpress";
$connectionInfo = array( "Database"=>"dbName", "UID"=>"username", "PWD"=>"password" );
$conn = sqlsrv_connect( $serverName, $connectionInfo);
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}