如何将每个整数"one by one"相乘并显示结果"in progressive order"，直到所有整数相乘得出总积

Question

最近，我尝试创建一个 for 循环，将列表中的每个整数与 returns 每个顺序乘积相乘，直到给出所有整数的总乘积。

import operator
from operator import mul
from functools import reduce


s = list(map(int, input('Enter numbers WITH SPACES: ').split(' ')))


progression_product = [];
for i in s:
      progression_product.append(reduce(mul, s[0:i]))

#This loop below removes repeating results. As for progressive order multiplication of positive
#integers. It's impossible to have a repeating result.(excluding multiple 1's and 0)

for ss in progression_product:
  if progression_product.count(ss) > 1:
    progression_product.remove(ss)

print(progression_product)

- 请注意，输出会跳过下面 13 的结果。但是在列出的输出末尾正确完成所有整数的总乘积

Enter numbers WITH SPACES: 12 2 3 4 13 133
[24, 72, 288, 497952]
> 12*2*3*4*13
>3744

问题

有什么办法可以解决这个问题吗？为什么 python 会跳过 13 处的结果？还有，我该如何解决？

Answer 1

您正在迭代 s 的元素，而不是索引。在删除重复项之前打印列表，它将是：

[497952, 24, 72, 288, 497952, 497952]
# Which are the products of:
[s[0:12], s[0:2], s[0:3], s[0:4], s[0:13], s[0:133]]

用索引循环替换第一个循环，通过 range(len(s)) 或 enumerate(s):

# Either this:
progression_product = [];
for i in range(len(s)):
      progression_product.append(reduce(mul, s[0:i]))

# Or this:
progression_product = [];
for i, v in enumerate(s):
      progression_product.append(reduce(mul, s[0:i]))

如何将每个整数"one by one"相乘并显示结果"in progressive order"，直到所有整数相乘得出总积

How to multiply each integer "one by one" and display result "in progressive order" until all integers multiplied leads to the overall product

multiplication

python-3.x

问题