AttributeError: 'Series' object has no attribute 'isoweekday'
AttributeError: 'Series' object has no attribute 'isoweekday'
我写了一个函数,将日期移动到周末和节假日的指定工作日数。当我将它与标量值一起使用时它工作正常但是我在尝试在 pandas DataFrame 上使用时遇到问题。
函数本身如下所示:
def move_date_by_days(init_date, roll=1, nwd_key=None, hol_key=None):
'''
moves date by n-number of working days forward or backward
init_date: date, initial caluclation date
roll: integer, number of days to move forward (+) or backward (-)
nwd_key: string that stands for currency iso code, it is a key in non_working_days dictionary
hol_key: string that stands for currency iso code, it is a key in holidays dictonary
return: date
'''
nwd = non_working_days.get(nwd_key, [])
hol = holidays.get(hol_key,[])
moved_date = init_date + datetime.timedelta(days=roll)
if (moved_date.isoweekday() in nwd) or (moved_date in hol):
if roll >= 0:
moved_date=move_date_by_days(init_date + datetime.timedelta(days=1), roll=roll, nwd_key=nwd_key, hol_key=hol_key)
else:
moved_date=move_date_by_days(init_date + datetime.timedelta(days=-1), roll=roll, nwd_key=nwd_key, hol_key=hol_key)
return moved_date
现在,我有包含列 'start_date' 和 'end_date'
的 DataFrame 'df'
start_date end_date
0 2020-01-31 2020-04-30
1 2020-04-30 2020-07-31
2 2020-07-31 2020-10-31
3 2020-10-31 2020-11-28
我想创建名为 'fixing' 的第三列,该列将比 'start_date' 早 2 个工作日。我正在尝试这个:
dates_table['fixing'] = move_date_by_days(self.dates_table['start_date'], -2, self.ccy, self.ccy)
但是 returns AttributeError: 'Series' object has no attribute 'isoweekday'
请注意,当我引用 DataFrame 的标量数据时,该函数工作正常,例如
d1 = s1.dates_table.iat[0,0]
move_date_by_days(d1, -2, 'pln', 'pln')
它 returns 我所期望的:datetime.date(2020, 1, 29)
请问如何在数据框的整列上使用该函数?
IIUC,为什么不使用 offsets.BDay
or offsets.CustomBusinessDay
列表 holidays
:
df['fixing'] = df['start_date'] - pd.offsets.BDay(2)
df['fixing'] = df['start_date'] - pd.offsets.CustomBusinessDay(2, holidays=holidays['pln'])
[出局]
start_date end_date fixing
0 2020-01-31 2020-04-30 2020-01-29
1 2020-04-30 2020-07-31 2020-04-28
2 2020-07-31 2020-10-31 2020-07-29
3 2020-10-31 2020-11-28 2020-10-29
我写了一个函数,将日期移动到周末和节假日的指定工作日数。当我将它与标量值一起使用时它工作正常但是我在尝试在 pandas DataFrame 上使用时遇到问题。 函数本身如下所示:
def move_date_by_days(init_date, roll=1, nwd_key=None, hol_key=None):
'''
moves date by n-number of working days forward or backward
init_date: date, initial caluclation date
roll: integer, number of days to move forward (+) or backward (-)
nwd_key: string that stands for currency iso code, it is a key in non_working_days dictionary
hol_key: string that stands for currency iso code, it is a key in holidays dictonary
return: date
'''
nwd = non_working_days.get(nwd_key, [])
hol = holidays.get(hol_key,[])
moved_date = init_date + datetime.timedelta(days=roll)
if (moved_date.isoweekday() in nwd) or (moved_date in hol):
if roll >= 0:
moved_date=move_date_by_days(init_date + datetime.timedelta(days=1), roll=roll, nwd_key=nwd_key, hol_key=hol_key)
else:
moved_date=move_date_by_days(init_date + datetime.timedelta(days=-1), roll=roll, nwd_key=nwd_key, hol_key=hol_key)
return moved_date
现在,我有包含列 'start_date' 和 'end_date'
的 DataFrame 'df' start_date end_date
0 2020-01-31 2020-04-30
1 2020-04-30 2020-07-31
2 2020-07-31 2020-10-31
3 2020-10-31 2020-11-28
我想创建名为 'fixing' 的第三列,该列将比 'start_date' 早 2 个工作日。我正在尝试这个:
dates_table['fixing'] = move_date_by_days(self.dates_table['start_date'], -2, self.ccy, self.ccy)
但是 returns AttributeError: 'Series' object has no attribute 'isoweekday'
请注意,当我引用 DataFrame 的标量数据时,该函数工作正常,例如
d1 = s1.dates_table.iat[0,0]
move_date_by_days(d1, -2, 'pln', 'pln')
它 returns 我所期望的:datetime.date(2020, 1, 29)
请问如何在数据框的整列上使用该函数?
IIUC,为什么不使用 offsets.BDay
or offsets.CustomBusinessDay
列表 holidays
:
df['fixing'] = df['start_date'] - pd.offsets.BDay(2)
df['fixing'] = df['start_date'] - pd.offsets.CustomBusinessDay(2, holidays=holidays['pln'])
[出局]
start_date end_date fixing
0 2020-01-31 2020-04-30 2020-01-29
1 2020-04-30 2020-07-31 2020-04-28
2 2020-07-31 2020-10-31 2020-07-29
3 2020-10-31 2020-11-28 2020-10-29