在 .CSV 文件中为 XML 解析创建 XSL

Question

使用 XSL 解析的 .CSV 文件中以下提到的 XML 文件的预期结果

样本XML文件

 <SCHOLARSHIP>
    <SCHOLARSHIP_DTL>
    <SCHOLARSHIP_NAME>Sports SCHOLARSHIP</SCHOLARSHIP_NAME>
    <ISSUE_DATE>21/12/2019</ISSUE_DATE>
    <AMOUNT>40000</AMOUNT>
    <STUDENTS>
    <STUDENT>
    <STUDENT_NAME>Alex</STUDENT_NAME>
    <SCHOOL_NAME>Monten</SCHOOL_NAME>
    </STUDENT>
    <STUDENT>
    <STUDENT_NAME>Lena</STUDENT_NAME>
    <SCHOOL_NAME>Convent</SCHOOL_NAME>
    </STUDENT>
    </STUDENTS>
    </SCHOLARSHIP_DTL>
 </SCHOLARSHIP>

使用 Xsl 解析上述示例数据的 .csv 格式的预期输出

 SCHOLARSHIP_NAME,ISSUE_DATE,AMOUNT,STUDENT_NAME,SCHOOL_NAME
 Sports SCHOLARSHIP,21/12/2019,40000,Alex,Monten
 Sports SCHOLARSHIP,21/12/2019,40000,Lena,Convent

下面提到的 xsl 没有得到多个学生

    <xsl:template match="/">
     SCHOLARSHIP_NAME,ISSUE_DATE,AMOUNT,STUDENT_NAME,SCHOOL_NAME
    <xsl:for-each select="SCHOLARSHIP/SCHOLARSHIP_DTL"> 
    <xsl:value-of select="concat(SCHOLARSHIP_NAME,',',ISSUE_DATE,',',AMOUNT,',',STUDENTS/STUDENT/STUDENT_NAME,',',STUDENTS/STUDENT/SCHOOL_NAME,'&#xA;')"/>

Answer 1

不处理带引号的字符串的简单方法是以下 XSLT-1.0 样式表：

<xsl:template match="/">
    SCHOLARSHIP_NAME,ISSUE_DATE,AMOUNT,STUDENT_NAME,SCHOOL_NAME
    <xsl:for-each select="SCHOLARSHIP/SCHOLARSHIP_DTL"> 
        <xsl:for-each select="STUDENTS/STUDENT"> 
            <xsl:value-of select="concat(../../SCHOLARSHIP_NAME,',',../../ISSUE_DATE,',',../../AMOUNT,',',STUDENT_NAME,',',SCHOOL_NAME,'&#xA;')"/>
        </xsl:for-each>
    </xsl:for-each>
</xsl:template>

它的输出是：

SCHOLARSHIP_NAME,ISSUE_DATE,AMOUNT,STUDENT_NAME,SCHOOL_NAME
Sports SCHOLARSHIP,21/12/2019,40000,Alex,Monten
Sports SCHOLARSHIP,21/12/2019,40000,Lena,Convent

指定为顶级元素（xsl:stylesheet 的子元素）的首选输出方法应该是 "text"，如下所示：

<xsl:output method="text" />

在 .CSV 文件中为 XML 解析创建 XSL

XSL Creation for XML Parsing in .CSV File

xml

csv

xslt

xslt-1.0

xml-parsing