JSON 将数组与字符串数组组合以获得内聚的名称值对

Question

我的应用程序正在利用第 3 方应用程序获取数据 (Splunk)。 Splunks api 端点 returns 的输出是一个包含所有行 headers 的数组和一个包含所有行数据的字符串数组。例如

{
    "fields":[
        "appID",
        "ApplicationName",
        "AppOwner",
        "AppOwnerID",
        "KnownIPS",
        "IP Count",
        "KnownFIDS",
        "FIDCount",
        "LastSeen",
        "TotalConnections"],
    "rows":[
        [
            "123456",
            "HelloWorld",
            "Last,First",
            "E12345",
            "11.111.11.111,222.22.22.222",
            "2",
            "A67890,B12345,C67890",
            "3",
            "2019-12-08",
            "47937"
        ]
    ],
    "id":0
}

但是我希望我的输出类似于

{
    Field[0]:row[0],
    Field[1]:row[1],
    etc..
}

现在我可以使用以下方法在我的网页上显示结果

 try {

        ArrayList<String> fieldslist = new ArrayList<String>();

        JSONObject json = new JSONObject(responseString);
        JSONArray fields = json.getJSONArray("fields");

        JSONArray jsonArray = json.getJSONArray("rows"); // JSONArray is from the json.org library
        String[][] arrayOfArrays = new String[jsonArray.length()][];
        for (int i = 0; i < jsonArray.length(); i++) {
            JSONArray innerJsonArray = (JSONArray) jsonArray.get(i);
            String[] stringArray = new String[innerJsonArray.length()];
            for (int j = 0; j < innerJsonArray.length(); j++) {
                stringArray[j] = (String) innerJsonArray.get(j);
            }
            arrayOfArrays[i] = stringArray;
        }



        if (fields != null) {
            int len = fields.length();
            for (int i=0;i<len;i++){
                fieldslist.add(fields.get(i).toString());

            }
        } ;

        appDetail.setFields(fieldslist);
        appDetail.setRows(arrayOfArrays);

    } catch (JSONException e) {
        e.printStackTrace();
    }

    return appDetail;

还有我的模特

@JsonProperty("fields")
private List<String> fields = new ArrayList<String>();
@JsonProperty("rows")
private String[][] rows = new String[i][j];

@JsonProperty("fields")
public List<String> getFields() {
    return fields;
}

@JsonProperty("fields")
public void setFields(List<String> fields) {
    this.fields = fields;
}

public Model withFields(List<String> fields) {
    this.fields = fields;
    return this;
}

@JsonProperty("rows")
public String[][] getRows() {
    return rows;
}

@JsonProperty("rows")
public void setRows(String[][] rows) {
    this.rows = rows;
}

public Model withRows(String[][] rows) {
    this.rows = rows;
    return this;

我知道我必须更新我的模型才能正确显示正确的结果，但我似乎无法在 try catch 中获得正确的逻辑。

Answer 1

一个简单的方法是将fields的对象的响应转换为List<String>，rows转换为List<List<String>>，然后您可以将预期结果显示为如下。

Class SplunkResponse

class SplunkResponse {
    private List<String> fields;
    private List<List<String>> rows;
    private int id;

    //general getters ans setters
}

代码段

ObjectMapper mapper = new ObjectMapper();
SplunkResponse response = mapper.readValue(jsonStr, SplunkResponse.class);
Map<String, Object> resultMap = new HashMap<>();
for (int row = 0; row < response.getRows().size(); row++) {
    for (int idx = 0; idx < response.getRows().get(row).size(); idx++) {
        resultMap.put(response.getFields().get(idx), response.getRows().get(row).get(idx));
    }
}

System.out.println(mapper.writeValueAsString(resultMap));

控制台输出

{"IP Count":"2","ApplicationName":"HelloWorld","AppOwner":"Last,First","KnownFIDS":"A67890,B12345,C67890","KnownIPS":"11.111.11.111,222.22.22.222","appID":"123456","AppOwnerID":"E12345","FIDCount":"3","TotalConnections":"47937","LastSeen":"2019-12-08"}

JSON 将数组与字符串数组组合以获得内聚的名称值对

JSON Combine Array with Array of Strings to get a cohesive name value pair

java

json

splunk