在 C 中，引用命名结构成员直接初始化或分配变量数组的结构成员？

Question

在关于 SO 和其他地方的类似问题中，在这种情况下所讨论的唯一解决方案是使用数组表示法初始化结构数组，而不是使用结构成员的点名。最接近我想要的是使用以下代码：

int texturesCount = 2;
struct textureParams textures[texturesCount];
struct textureParams textures0 =   {
                                        .textureFormat = textureFormat,
                                        .textureAccess = textureAccess,
                                        .srcrect = {.x = 0, .y = 0, .w = 50, .h = 50},
                                        .dstrect = {.x = 0, .y = 500, .w = 50, .h = 50},
                                        .r = 255,
                                        .g = 0,
                                        .b = 0,
                                        .a = 0,
                                    };
struct textureParams textures1 =   {
                                        .textureFormat = textureFormat,
                                        .textureAccess = textureAccess,
                                        .srcrect = {.x = 0, .y = 0, .w = 20, .h = 20},
                                        .dstrect = {.x = 10, .y = 100, .w = 20, .h = 20},
                                        .r = 0,
                                        .g = 255,
                                        .b = 0,
                                        .a = 0,
                                    };
textures[0] = textures0;
textures[1] = textures1;

有没有办法做到这一点 - 创建数组的结构成员并引用命名的结构成员 - 但不创建临时变量 texture0 和 texture1？

Answer 1

例如，如果您要创建一个 int 的数组，您可以像这样初始化它：

int arr[3] = { 3, 4, 5 };

在你的情况下是一样的，除了它是一个结构数组，并且每个初始化器都是一个结构初始化器：

struct textureParams textures[texturesCount] = {
    {
        .textureFormat = textureFormat,
        .textureAccess = textureAccess,
        .srcrect = {.x = 0, .y = 0, .w = 50, .h = 50},
        .dstrect = {.x = 0, .y = 500, .w = 50, .h = 50},
        .r = 255,
        .g = 0,
        .b = 0,
        .a = 0,
    },
    {
        .textureFormat = textureFormat,
        .textureAccess = textureAccess,
        .srcrect = {.x = 0, .y = 0, .w = 20, .h = 20},
        .dstrect = {.x = 10, .y = 100, .w = 20, .h = 20},
        .r = 0,
        .g = 255,
        .b = 0,
        .a = 0,
    }
};

Answer 2

是的，您可以使用复合文字直接分配给数组的成员：

    int texturesCount = 2;
    struct textureParams textures[texturesCount];

    textures[0] = (struct textureParams) {
            .textureFormat = textureFormat,
            .textureAccess = textureAccess,
            .srcrect = {.x = 0, .y = 0, .w = 50, .h = 50},
            .dstrect = {.x = 0, .y = 500, .w = 50, .h = 50},
            .r = 255,
            .g = 0,
            .b = 0,
            .a = 0,
    };
    textures[1] = (struct textureParams) {
            .textureFormat = textureFormat,
            .textureAccess = textureAccess,
            .srcrect = {.x = 0, .y = 0, .w = 20, .h = 20},
            .dstrect = {.x = 0, .y = 100, .w = 20, .h = 20},
            .r = 0,
            .g = 255,
            .b = 0,
            .a = 0,
    };

在 C 中，引用命名结构成员直接初始化或分配变量数组的结构成员？

Initializing or assigning struct members of variable array directly, with reference to named struct members, in C?

c

arrays

struct

initialization

variable-assignment