gorm 没有任何错误地创建表失败

Question

我正在使用 postgres 和 gorm。这是我的模型：

package models

import "github.com/jinzhu/gorm"

type User struct {
    gorm.Model
    Username  string `gorm:"unique_index;not null"`
    Hash      string `gorm:"not null"`
    IsAdmin   bool   `gorm:"not null"`
    IsUser    bool   `gorm:"not null"`
    IsActive  bool   `gorm:"not null"`
    RegEmail  bool   `gorm:"not null"`
    RegFb     bool   `gorm:"not null"`
    RegGoogle bool   `gorm:"not null"`
}

type NewsPaper struct {
    gorm.Model
    Name     string `gorm:"not null"`
    NamBN    string `gorm:"not null"`
    LogoUrl  string `gorm:"not null"`
    Slug     string `gorm:"unique_index;not null"`
    IsActive bool   `gorm:"not null"`
    IsWeb    bool   `gorm:"not null"`
    IsMobile bool   `gorm:"not null"`
}

和数据库功能：

package bootstrap

import (
    "fmt"
    "github.com/jinzhu/gorm"
    _ "github.com/jinzhu/gorm/dialects/postgres"
    "github.com/u/projName/models"
)

var db *gorm.DB

// initialize database
func Init() {
    var adapter string
    adapter = App.DBConfig.String("adapter")
    switch adapter {
    case "postgres":
        postgresConn()
        break
    default:
        panic("Undefined connection on config.local.yaml")
    }
}

func postgresConn() {
    var (
        connectionString string
        err              error
    )
    connectionString = fmt.Sprintf("connection info")
    if db, err = gorm.Open("postgres", connectionString); err != nil {
        panic(err)
    }
    if err = db.DB().Ping(); err != nil {
        panic(err)
    }

    db.LogMode(true)
}

//Gorm: return GORM's postgres database connection instance.
func DBManager() *gorm.DB {
    var adapter string
    adapter = App.DBConfig.String("adapter")
    switch adapter {
    case "postgres":
        postgresConn()
        break
    default:
        panic("Undefined connection on config.yaml")
    }
    err := db.AutoMigrate(&models.NewsPaper{}, &models.User{}).Error
    if err != nil {
        panic(err)
    }
    return db
}

当我运行主函数时，它不会抛出任何错误。我检查了数据库没有 table.

Answer 1

你必须用你的模型调用 gorm migrate 函数。

db.AutoMigrate(&User{},&NewsPaper{})

它将为您的模型创建 table。

gorm 没有任何错误地创建表失败

gorm failed to create tables without any errors

go

go-gorm