无法在 Ansible 中打印具有正则表达式匹配结果的变量

Question

下面是我的剧本，它搜索字符串 "SSLFile" 并将匹配结果存储在名为 "target"

的 set_fact 中

- name: Find certificate entries
  set_fact:
    target: "{{ filecontent.stdout | regex_findall('\sSSLFile.*') }}"

- debug:
    msg: "{{ target }}"

上面的调试输出显示了三个匹配的行。请参阅下面的输出：

TASK [Find certificate entries] ***************************************
task path: /app/test.yml:908
ok: [10.9.9.11] => {
    "ansible_facts": {
        "target": [
            " SSLFile  /web/test1.crt", 
            " SSLFile  /web/SSL.crt", 
            " SSLFile  /web/test.crt"
        ]
    }, 
    "changed": false
}

我只想获取文件名，即来自变量 "target" 的第 2 列，即

/web/test1.crt
/web/SSL.crt
/web/test.crt

我尝试了以下方法，但其中 none 有效并给出错误：

    - name: Print found entries
      debug:
        msg: "{{ item.split()[1] }}"
      with_items: "{{ target.split(',') }}"

此外，尝试了以下方法：

 with_items: "{{ target.results }}"
 with_items: "{{ target.stdout_lines }}"
 with_items: "{{ target.stdout }}"

收到错误：

TASK [debug] *******************************************************************
task path: /app/test.yml:917
fatal: [10.9.9.11]: FAILED! => {
    "msg": "The task includes an option with an undefined variable. The error was: 'list object' has no attribute 'split'\n\nThe error appears to be in '/app/test.yml': line 917, column 7, but may\nbe elsewhere in the file depending on the exact syntax problem.\n\nThe offending line appears to be:\n\n\n    - debug:\n      ^ here\n"
}

Answer 1

变量target是一个列表。迭代它是可能的。任务

    - debug:
        msg: "{{ item.split()[1] }}"
      loop: "{{ target }}"

给予

    "msg": "/web/test1.crt"
    "msg": "/web/SSL.crt"
    "msg": "/web/test.crt"

无法在 Ansible 中打印具有正则表达式匹配结果的变量

Unable to print variable having regex match results in Ansible

regex

runtime-error

stdout

exception

ansible