如何遍历每个源文件并将特定列复制到新工作簿中，每个新 "paste" 转移到相邻列？

Question

我有 3 个 Excel 文件，每个工作簿（在 sheet 每个工作簿中有 1 个）。我想将源单元格中的数据复制到新工作簿中，但数据每次都必须移到新列中。
例如：

必须将文件 1 中的源单元格复制到新工作簿中的单元格 A1 到 A10；
必须将文件 2 中的源单元格复制到新工作簿中的单元格 B1 到 B10；和
必须将文件 3 中的源单元格复制到新工作簿中的单元格 C1 到 C10。

我正在努力想出在每次迭代中调整我的代码中的 "j" 的最佳方法。我也不确定运行不同源文件的每个函数的最简洁方法是什么。

关于如何使此代码更清晰的所有建议也将不胜感激，因为我承认现在它太乱了！

提前致谢！

import openpyxl as xl

filename_1 = "C:\workspace\scripts\file1.xlsx"
filename_2 = "C:\workspace\scripts\file2.xlsx"
filename_3 = "C:\workspace\scripts\file3.xlsx"

destination_filename = "C:\workspace\scripts\new_file.xlsx"

num_rows = 10
num_columns = 1


def open_source_workbook(path):
    '''Open the workbook and worksheet in the source Excel file'''
    workbook = xl.load_workbook(path)
    worksheet = workbook.worksheets[0]
    return worksheet

def open_destination_workbook(path):
    '''Open the destination workbook I want to copy the data to.'''
    new_workbook = xl.load_workbook(path)
    return new_workbook

def open_destination_worksheet(path):
    '''Open the worksheet of the destination workbook I want to copy the data to.'''
    new_worksheet = new_workbook.active
    return new_worksheet

def copy_to_new_file(worksheet, new_worksheet):
    for i in range (1, num_rows + 1):
        for j in range (1, num_columns + 1):
            c = worksheet.cell(row = i, column = j)
            new_worksheet.cell(row = i, column = j).value = c.value

worksheet = open_source_workbook(filename_1)
new_workbook = open_destination_workbook(destination_filename)
new_worksheet = open_destination_worksheet(new_workbook)
copy_to_new_file(worksheet, new_worksheet)
new_workbook.save(str(destination_filename))

Answer 1

Question: Loop files, copy a specific column, with each new “paste” shifting to the adjacent column?

此方法首先从 all 文件中聚合列单元格值。
然后重新排列它，使其可以被 openpyxl.append(... 方法使用。
因此，不需要目标列知识。

参考：

class collections.OrderedDict([items])

Ordered dictionaries are just like regular dictionaries but have some extra capabilities relating to ordering operations.
openpyxl.utils.cell.coordinate_to_tuple(coordinate)

Convert an Excel style coordinate to (row, colum) tuple
iter_rows(min_row=None, max_row=None, min_col=None, max_col=None, values_only=False)

Produces cells from the worksheet, by row. Specify the iteration range using indices of rows and columns.
map(function, iterable, ...)

Return an iterator that applies function to every item of iterable, yielding the results.
zip(*iterables)

Make an iterator that aggregates elements from each of the iterables.

二手进口

import openpyxl as opxl
from collections import OrderedDict

定义OrderedDict中的文件以保留文件<=>列顺序

file = OrderedDict.fromkeys(('file1', 'file2', 'file3'))

将范围定义为索引值。将 Excel A1 表示法转换为索引值

min_col, max_col, min_row, max_row =  
    opxl.utils.cell.range_to_tuple('DUMMY!A1:A10')[1]

循环定义的文件，
加载每个工作簿并获取对默认工作表的引用
从定义的范围中获取单元格值：
min_col=1, max_col=1, min_row=1, max_row=10

for fname in file.keys(): 
    wb = openpyxl.load_workbook(fname)
    ws = wb.current()
    file[fname] =  ws.iter_rows(min_row=min_row, 
                                max_row=max_row,
                                min_col=min_col,
                                max_col=max_col, 
                                values_only=True)

定义一个新工作簿并获取对默认工作表的引用
```
wb2 = opxl.Workbook()
ws2 = wb2.current()
```

压缩所有文件中的值，每行一行
使用 lambda 将压缩的元组列表映射为一个行值列表。
将值列表附加到新工作表

for row_value in map(lambda r:tuple(v for c in r for v in c), 
                     zip(*(file[k] for k in file))
                    ):
    ws2.append(row_value)

保存新工作簿
```
# wb2.save(...)
```

如何遍历每个源文件并将特定列复制到新工作簿中，每个新 "paste" 转移到相邻列？

How do I loop through each source file and copy a specific column into a new workbook with each new "paste" shifting to the adjacent column?

python

copy-paste

openpyxl