Pandas `transform(set)` 引发异常

Question

我正尝试通过 set 进行转换，但出现异常。 Transform 适用于 "sum" 和许多其他聚合函数，但不适用于 set 或 list.

>>> import pandas as pd
>>> df = pd.DataFrame({"a":[1,2,1,], "b":[1,1,2]})
>>> df
   a  b
0  1  1
1  2  1
2  1  2
>>> df.groupby("a").b.transform(set)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/Users/avloss/conda/lib/python3.7/site-packages/pandas/core/groupby/generic.py", line 1032, in transform
    s = klass(res, indexer)
  File "/Users/avloss/conda/lib/python3.7/site-packages/pandas/core/series.py", line 282, in __init__
    "{0!r} type is unordered" "".format(data.__class__.__name__)
TypeError: 'set' type is unordered

我期待的是：

   a      b   
0  1  {1, 2}
1  2     {1}
2  1  {1, 2}

Answer 1

我们有unique，请注意unique甚至会保留您输入的原始顺序

df.groupby('a').b.transform('unique')
0    [1, 2]
1       [1]
2    [1, 2]
Name: b, dtype: object

如果上述方法无效，请更新 , 试试下面

df.groupby('a').b.transform(lambda x : [set(x)]*len(x))
0    {1, 2}
1       {1}
2    {1, 2}
Name: b, dtype: object

Answer 2

我能想到的最简单的方法是 aggregate 作为 set 并将其映射回去

df['new_col'] = df['a'].map(df.groupby('a')['b'].agg(set))
print(df)

   a  b new_col
0  1  1  {1, 2}
1  2  1     {1}
2  1  2  {1, 2}

Pandas `transform(set)` 引发异常

Pandas `transform(set)` raising exception

python

transform

set

dataframe

pandas