一个数组的多个值 php - Mssql
multiple values an array php - Mssql
我正在从 mssql 中提取数据。我捕获的数据不止一个。它只记录一个数据到Array。如图所示,soru_tur = 1 的内容不止一个。如何将soru_baslik 和soru_icerik 数据保存到数组中?我展示了我在 swift 应用程序中捕获的数据。 var_dump 输出中添加了数据库屏幕截图。
" json["soru_baslik"] " >> 我想从 swift 打印出来。输出截图如下
<?php
...
$conn = sqlsrv_connect( $serverName, $connectionInfo );
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}
$json = file_get_contents('php://input');
$sql = "SELECT soru_baslik, soru_icerik FROM ... WHERE soru_tur = 1";
$stmt = sqlsrv_query( $conn, $sql );
if( $stmt === false) {
die( print_r( sqlsrv_errors(), true) );
}
$soruArray = array();
$soruicerikArray = array();
$array = array();
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) {
$results[] = Array("soru_baslik" => $row['soru_baslik'], "soru_icerik" => $row['soru_icerik']);
}
//var_dump($array);
echo '<pre>'; print_r($results); echo '</pre>';
sqlsrv_free_stmt( $stmt);
?>
如果我对你的问题的理解正确,你的代码的一个问题是你在每次迭代时初始化 $result
变量。您需要初始化此变量一次,然后在每次迭代时追加项目。您可以尝试以下方法:
示例 1(仅获取两个特定列):
<?php
$conn = sqlsrv_connect( $serverName, $connectionInfo );
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}
$json = file_get_contents('php://input');
$sql = "SELECT soru_baslik, soru_icerik FROM ... WHERE soru_no = 1";
$stmt = sqlsrv_query($conn, $sql);
if ($stmt === false) {
die( print_r( sqlsrv_errors(), true) );
}
$results = array();
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) {
$results[] = array(
"..._baslik" => $row['..._baslik'],
"s..._icerik" => $row['..._icerik']
);
}
header("Content-Type: application/json");
echo json_encode($results);
sqlsrv_free_stmt( $stmt);
?>
示例 2(获取所有列):
<?php
$conn = sqlsrv_connect( $serverName, $connectionInfo );
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}
$json = file_get_contents('php://input');
$sql = "SELECT soru_baslik, soru_icerik FROM ... WHERE soru_no = 1";
$stmt = sqlsrv_query($conn, $sql);
if ($stmt === false) {
die( print_r( sqlsrv_errors(), true) );
}
$results = array();
while ($row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) {
$a = array();
foreach($row as $column => $value) {
$a[$column] = $value;
}
$results[] = $a;
}
header("Content-Type: application/json");
echo json_encode($results);
sqlsrv_free_stmt( $stmt);
?>
我正在从 mssql 中提取数据。我捕获的数据不止一个。它只记录一个数据到Array。如图所示,soru_tur = 1 的内容不止一个。如何将soru_baslik 和soru_icerik 数据保存到数组中?我展示了我在 swift 应用程序中捕获的数据。 var_dump 输出中添加了数据库屏幕截图。
" json["soru_baslik"] " >> 我想从 swift 打印出来。输出截图如下
<?php
...
$conn = sqlsrv_connect( $serverName, $connectionInfo );
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}
$json = file_get_contents('php://input');
$sql = "SELECT soru_baslik, soru_icerik FROM ... WHERE soru_tur = 1";
$stmt = sqlsrv_query( $conn, $sql );
if( $stmt === false) {
die( print_r( sqlsrv_errors(), true) );
}
$soruArray = array();
$soruicerikArray = array();
$array = array();
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) {
$results[] = Array("soru_baslik" => $row['soru_baslik'], "soru_icerik" => $row['soru_icerik']);
}
//var_dump($array);
echo '<pre>'; print_r($results); echo '</pre>';
sqlsrv_free_stmt( $stmt);
?>
如果我对你的问题的理解正确,你的代码的一个问题是你在每次迭代时初始化 $result
变量。您需要初始化此变量一次,然后在每次迭代时追加项目。您可以尝试以下方法:
示例 1(仅获取两个特定列):
<?php
$conn = sqlsrv_connect( $serverName, $connectionInfo );
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}
$json = file_get_contents('php://input');
$sql = "SELECT soru_baslik, soru_icerik FROM ... WHERE soru_no = 1";
$stmt = sqlsrv_query($conn, $sql);
if ($stmt === false) {
die( print_r( sqlsrv_errors(), true) );
}
$results = array();
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) {
$results[] = array(
"..._baslik" => $row['..._baslik'],
"s..._icerik" => $row['..._icerik']
);
}
header("Content-Type: application/json");
echo json_encode($results);
sqlsrv_free_stmt( $stmt);
?>
示例 2(获取所有列):
<?php
$conn = sqlsrv_connect( $serverName, $connectionInfo );
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}
$json = file_get_contents('php://input');
$sql = "SELECT soru_baslik, soru_icerik FROM ... WHERE soru_no = 1";
$stmt = sqlsrv_query($conn, $sql);
if ($stmt === false) {
die( print_r( sqlsrv_errors(), true) );
}
$results = array();
while ($row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) {
$a = array();
foreach($row as $column => $value) {
$a[$column] = $value;
}
$results[] = $a;
}
header("Content-Type: application/json");
echo json_encode($results);
sqlsrv_free_stmt( $stmt);
?>