PHP 函数中的递归函数：如何防止 return 值？

Question

我正在研究 API 来获取数据，就像其他标准 API 一样，它限制了项目的 return 数量，例如在我的案例中，每页 return 只有 1 项。所以，我必须得到

total_count、
page_size（我的情况是 1），
和current_page_number.

问题是，无论我将它设置为递归，它仍然return第一个循环的值。例如如果总共有 3 个项目，并且每页限制为 1 个项目，它将 return 第一次循环中的值。

为什么以及如何解决这个问题？

非常感谢

function get_video_list($page_no = 0, $filter_video = array()) {
    $api = "http://api.brightcove.com/services/library?command=search_videos&page_size=1&video_fields=id%2Cname%2CcreationDate%2CFLVURL%2CpublishedDate%2ClinkURL%2CthumbnailURL%2Clength&media_delivery=http&sort_by=CREATION_DATE%3AASC&page_number=$page_no&get_item_count=true&token=" . READ_TOKEN;

    try {
        $ch = curl_init();

        if (FALSE === $ch) {
            throw new Exception('failed to initialize');
        }

        curl_setopt($ch, CURLOPT_URL, $api);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

        $content = curl_exec($ch);

        if (FALSE === $content) {
            throw new Exception(curl_error($ch), curl_errno($ch));
        }

        $video_list = json_decode($content, false, 512, JSON_BIGINT_AS_STRING);

        $page_number = ($video_list->page_number) + 1; //start at 0
        $page_size = $video_list->page_size;
        $total_count = $video_list->total_count;

        foreach ($video_list->items as $video) {
            if (in_array($video->id, $stored_video)) {
                $filter_video [] = $video;
            }
        }

        if ($total_count > $page_size * $page_number) {
            get_video_list($page_number, $filter_video);
        }

        return $filter_video;
    } catch (Exception $e) {
        trigger_error(sprintf('Curl failed with error #%d: %s', $e->getCode(), $e->getMessage()), E_USER_ERROR);
    }
}

Answer 1

这应该可以解决您的问题。

if ($total_count > $page_size * $page_number) {
      return get_video_list($page_number, $filter_video);
}

Answer 2

您没有将递归回调的 return 值分配给 $filter_video，更改为：

if ($total_count > $page_size * $page_number) {
    $filter_video = get_video_list($page_number, $filter_video);
}

或者，甚至更好：通过引用传递。这完全消除了对 return 值的需要，这对递归函数特别有用（注意函数声明中的 &$filter_video，参见 http://php.net/manual/en/language.references.pass.php）。

function get_video_list($page_no = 0, &$filter_video = array()) {
    $api = "http://api.brightcove.com/services/library?command=search_videos&page_size=1&video_fields=id%2Cname%2CcreationDate%2CFLVURL%2CpublishedDate%2ClinkURL%2CthumbnailURL%2Clength&media_delivery=http&sort_by=CREATION_DATE%3AASC&page_number=$page_no&get_item_count=true&token=" . READ_TOKEN;

    try {
        $ch = curl_init();

        if (FALSE === $ch) {
            throw new Exception('failed to initialize');
        }

        curl_setopt($ch, CURLOPT_URL, $api);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

        $content = curl_exec($ch);

        if (FALSE === $content) {
            throw new Exception(curl_error($ch), curl_errno($ch));
        }

        $video_list = json_decode($content, false, 512, JSON_BIGINT_AS_STRING);

        $page_number = ($video_list->page_number) + 1; //start at 0
        $page_size = $video_list->page_size;
        $total_count = $video_list->total_count;

        foreach ($video_list->items as $video) {
            if (in_array($video->id, $stored_video)) {
                $filter_video [] = $video;
            }
        }

        if ($total_count > $page_size * $page_number) {
            get_video_list($page_number, $filter_video);
        }
    } catch (Exception $e) {
        trigger_error(sprintf('Curl failed with error #%d: %s', $e->getCode(), $e->getMessage()), E_USER_ERROR);
    }
}

然后这样称呼它：

$myVideoList = [];
get_video_list(0, $myVideoList);

// Do stuff with $myVideoList

PHP 函数中的递归函数：如何防止 return 值？

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