TypeScript 中数字的扩展方法

Extension method on number in TypeScript

我读到可以 ,但是将其应用于内置类型 Number 时遇到了一些麻烦。

这是一些代码:

文件A:NumberExtensions.ts

// tslint:disable-next-line:class-name interface-name
export interface Number {
    isBigNumber(value: number): boolean;
}
// @ts-ignore
Number.prototype.isBigNumber = (value: number) => {
    return value > 100000;
};

文件B:使用上述

import { Number } from "./NumberExtensions";

foo() {
    const aBigNumber: number = 1000000000;

    // Errors here TS2339: Property 'isBigNumber' does not exist on type 'number'.
    if (aBigNumber.isBigNumber()) {
        console.log("It's a big number!");
    }
}

我对 TypeScript 扩展方法的声明和使用是否正确?

由于您在作为模块的文件中定义扩充,因此您需要在 declare global:

中添加扩充声明

export { }
declare global {
    export interface Number {
        isBigNumber(): boolean;
    }
}
Number.prototype.isBigNumber = function (this: number)  {
    return this > 100000;
};

function foo() {
    const aBigNumber: number = 1000000000;

    // Errors here TS2339: Property 'isBigNumber' does not exist on type 'number'.
    if (aBigNumber.isBigNumber()) {
        console.log("It's a big number!");
    }
}



Playground Link