使用 python 正则表达式仅提取第一个匹配项

Question

我有一个字符串如下：

course_name = "Post Graduate Certificate Programme in Retail Management (PGCPRM) (Online)"

我只想提取 'PGCPRM' 或第一个括号内值内的任何内容，并有一个新的课程名称如下：

course_name_new = "Post Graduate Certificate Programme in Retail Management (Online)"

Answer 1

您可以使用 str.replace() :

>>> course_name = "Post Graduate Certificate Programme in Retail Management (PGCPRM) (Online)"
>>> course_name.replace('(PGCPRM) ','')
'Post Graduate Certificate Programme in Retail Management (Online)'

编辑：如果你想替换 (Online) 之前的单词，你需要正则表达式和 positive look-behind:

>>> re.sub(r'(\(\w+\) )(?=\(Online\))','',course_name)
'Post Graduate Certificate Programme in Retail Management (Online)'

或者，如果您想删除第一个括号，请使用以下内容：

>>> re.sub(r'(\(\w+\) ).*?','',course_name)
'Post Graduate Certificate Programme in Retail Management (Online)'

并提取它使用 re.search :

>>> re.search(r'(\(.*?\))',course_name).group(0)
'(PGCPRM)'

Answer 2

很简单：

In [8]: course_name
Out[8]: 'Post Graduate Certificate Programme in Retail Management (PGCPRM) (Online)'

In [9]: print re.sub('\([A-Z]+\)\s*', '', course_name)
Post Graduate Certificate Programme in Retail Management (Online)

In [17]: print re.search('\(([A-Z]+)\)\s*', course_name).groups()[0]
PGCPRM

Answer 3

提取第一个括号内的值

>>> course_name = "Post Graduate Certificate Programme in Retail Management (PGCPRM) (Online)"
>>> x = re.search(r'\(.*?\)',course_name).group()
>>> x
'(PGCPRM)'

然后进行替换

>>> course_name.replace(x,'')
'Post Graduate Certificate Programme in Retail Management  (Online)'

使用 python 正则表达式仅提取第一个匹配项

Extract only first match using python regular expression

python

regex

string