如何在此 CosmosDB 查询中获取值属性？

Question

我试图更深入地了解一个对象，但由于某种原因它在我的 Cosmos 查询中不起作用，查询非常简单，如下所示。

SELECT c.id,  
c.ItemNo, 
bv.variantId AS variantNo, 
bv.variantDescription AS title, 
c.BasicData.presentation.articleLongDescription[0] AS Description,
c.BasicData.presentation.articleCompositionList.origin,
bv.size.sizeName,
c.BasicData.asset.assets[0].locations[1].path
FROM c
JOIN bv IN c.BasicData.base.sales.variants
WHERE c.brand = 'XXX'
AND c.Consumer = 'XXX'
AND bv.variantId = 'XXX'
AND c.Season = 'XXX'

结果也很直接如下

[
    {
        "id": "9c9c5b56-999f-4f98-8c52-902f43dd4cfe",
        "ItemNo": "0562168014",
        "variantNo": "0562168014003",
        "title": "Trousers Grey, 36",
        "Description": {
            "locale": "en-GB",
            "value": "jongel fibbel"
        },
        "origin": "{\"\":{\"materials\":{\"002elastane\":\"30.0\",\"002polyester\":\"70.0\"}}}",
        "path": "https://public.assets.XXX.com/assets/002/b0/1b/b01b4fa77023f48ca3c6ff8777cc27276f478f1e.jpg"
    }
]

我的问题是我想 return "value" 属性 "jongel fibbel" 而不是整个描述对象

我试着改变

c.BasicData.presentation.articleLongDescription[0] AS Description,

到

c.BasicData.presentation.articleLongDescription[0].value AS Description,

但这给了我一个语法错误值

我怎样才能 return 上述查询中的正确值？

编辑 ------

aricleLongDescription is an array as follows

"articleLongDescription": [
                {
                    "locale": "en-GB",
                    "value": "jongel fibbel"
                }
            ],

所以我也尝试了 JOIN 如下

SELECT c.id,  
c.ItemNo, 
bv.variantId AS variantNo, 
bv.variantDescription AS title, 
ba.value AS Description,
c.BasicData.presentation.articleCompositionList.origin,
bv.size.sizeName,
c.BasicData.asset.assets[0].locations[1].path
FROM c
JOIN bv IN c.BasicData.base.sales.variants
JOIN ba IN c.BasicData.presentation.articleLongDescription
WHERE c.brand = 'XXX'
AND c.Consumer = 'XXX'
AND bv.variantId = 'XXX'
AND c.Season = 'XXXX'

但它也因值

处的语法错误而失败

编辑 ---

也尝试了如下子查询

SELECT c.id,  
c.ItemNo, 
bv.variantId AS variantNo, 
bv.variantDescription AS title, 
--c.BasicData.presentation.articleLongDescription[0] AS Description,
-- ARRAY(SELECT serving.description FROM serving IN food.servings) AS servings
ARRAY(SELECT jongel.value FROM jongel IN c.BasicData.presentation.articleLongDescription) AS Description

c.BasicData.presentation.articleCompositionList.origin,
bv.size.sizeName,
c.BasicData.asset.assets[0].locations[1].path
FROM c
JOIN bv IN c.BasicData.base.sales.variants
JOIN ba IN c.BasicData.presentation.articleLongDescription
WHERE c.brand = 'XXX'
AND c.Consumer = 'XXX'
AND bv.variantId = 'XXX'
AND c.Season = 'XXX'

但它也因值的语法错误而失败，我想知道 "value" 是受保护的关键字还是 CosmosDB 中的某些内容？

Answer 1

事实证明 value 是 CosmosDB 中的保留关键字，因此绕过它的语法如下

c.BasicData.presentation.articleLongDescription[0]["value"] AS Description,

注意没有.（点）只有括号和双引号

如何在此 CosmosDB 查询中获取值属性？

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How do I get the value property in this CosmosDB QUery?

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如何在此 CosmosDB 查询中获取值属性？