如何在 html table 中填充 UNION ALL 查询数据

Question

如何在 html table 中填充数据，同时 header 和 PHP 都获取了数据，而 MYSQL.I 没有得到输出显示，因为我想得到，就像在想要的输出图像中一样。

$query = $db->prepare("SELECT player, score FROM cricket_table WHERE dateby BETWEEN '2020-01-01' AND '2020-03-01'
UNION ALL
SELECT player, score FROM football_table WHERE dateby BETWEEN '2020-01-01' AND '2020-03-01'");
$query->execute; 
echo '<table><tr><th>Player Name</th><th>Cricket</th><th>Football</th></tr>';
while($row = $query->fetch(PDO:: FETCH_ASSOC) ) {
echo '<tr>
        <td>'.$row['player'].'</td>
        <td>'.$row['score'].'</td>
     </tr>';
}
echo '</table>';

这是想要的output

这是当前输出

Answer 1

SELECT c.player, c.score AS cr_score, f.score AS fb_score FROM cricket_table c
INNER JOIN football_table f ON f.player=c.player AND (f.dateby BETWEEN '2020-01-01' AND '2020-03-01')
WHERE c.dateby BETWEEN '2020-01-01' AND '2020-03-01'

现在尝试输出 table，

while($row = $query->fetch(PDO:: FETCH_ASSOC) ) {
echo '<tr>
        <td>'.$row['player'].'</td>
        <td>'.$row['cr_score'].'</td>
        <td>'.$row['fb_score'].'</td>
     </tr>';
}

无法对其进行测试，但您了解了总体思路，应该可以工作

Answer 2

您可以使用 UNION ALL 并对每列所需的值求和：

这是你的SQL。请注意，它将运行都使用 union all 进行查询，然后对每个值求和。我们将使用“0”（零）技巧来忽略 "wrong" table:

SELECT x.player, SUM(x.cricket_score) as cricket_score, SUM(x.football_score) as football_score FROM (
    SELECT player, SUM(score) as cricket_score, 0 as football_score
      FROM cricket_table
     WHERE dateby BETWEEN '2020-01-01' AND '2020-03-01'
     GROUP BY player
     UNION ALL
    SELECT player, 0 as cricket_score, SUM(score) as football_score
      FROM football_table 
     WHERE dateby BETWEEN '2020-01-01' AND '2020-03-01'
     GROUP BY player
) x
GROUP BY x.player

并应用于代码：

$query = $db->prepare("    SELECT x.player, SUM(x.cricket_score) as cricket_score, SUM(x.football_score) as football_score FROM (
    SELECT player, SUM(score) as cricket_score, 0 as football_score
      FROM cricket_table
     WHERE dateby BETWEEN '2020-01-01' AND '2020-03-01'
     GROUP BY player
     UNION ALL
    SELECT player, 0 as cricket_score, SUM(score) as football_score
      FROM football_table 
     WHERE dateby BETWEEN '2020-01-01' AND '2020-03-01'
     GROUP BY player
) x
GROUP BY x.player");
$query->execute();
echo '<table><tr><th>Player Name</th><th>Cricket</th><th>Football</th></tr>';
while($row = $query->fetch(PDO:: FETCH_ASSOC) ) {
    echo '<tr>
        <td>'.$row['player'].'</td>
        <td>'.$row['cricket_score'].'</td>
        <td>'.$row['football_score'].'</td>
     </tr>';
}
echo '</table>';

有了这个 SQL 您将获得板球或足球已经设置的值。

如何在 html table 中填充 UNION ALL 查询数据

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