计数多维数组
Count multidimensional array
我有我的主数组:
array(6) {
[1]=> array(3) {
[0]=> string(15) "Extension"
[1]=> int(1)
[2]=> string(6) "3,00 "
}
[2]=> array(3) {
[0]=> string(32) "Physics "
[1]=> string(1) "1"
[2]=> string(6) "3,00 "
}
[3]=> array(3) {
[0]=> string(31) "Physics "
[1]=> int(1)
[2]=> string(6) "6,00 "
}
[4]=> array(3) {
[0]=> string(34) "Desk"
[1]=> int(4)
[2]=> string(8) "127,00 "
}
[5]=> array(3) {
[0]=> string(18) "assistance"
[1]=> int(1)
[2]=> string(7) "12,50 "
}
[6]=> array(3) {
[0]=> string(15) "Extension"
[1]=> int(1)
[2]=> string(6) "3,00 "
}
}
我的预期输出是:
Extension 2
Physics 2
Desk 1
Assistance 1
结果必须在结果数组中
我能怎么做?我尝试使用 array_count_values 函数但不起作用。
我如何购买 answear:
我试过这段代码,但它不起作用
$tabrecap = array();
foreach($counts as $key=>$value){
//echo $key." qte".$value;
$tabrecap = array ($key,$value,$valueOption);
}
只做一个循环并使用每个数组的第一项作为键:
$array = array(
array("Extension", 1, "3,00"),
array("Physics", "1", "3,00"),
array("Physics", 1, "6,00 ")
);
$count = array();
foreach($array as $a)
$count[$a[0]]++;
var_dump($count); // array(2) { ["Extension"]=> int(1) ["Physics"]=> int(2) }
循环就是答案。
<?php
// untested
$counts = Array();
foreach( $array as $subArray ){
$value = $subArray[0];
$counts[ $value ] = ( isset($counts[ $value ]) )
? $counts[ $value ] + 1
: 1;
}
var_dump( $counts);
正如你在评论中所问的,请试试这个:-
<?php
$array = array( '1'=> array('0'=>"Extension", '1'=> 1, '2'=>"3,00 " ), '2'=> array('0'=>"Physics",'1'=>"1","3,00 " ),'3'=> array('0'=>"Physics",'1'=>1,"6,00 "),'4'=> array('0'=>"Desk",'1'=>4,"127,00 "),'5'=> array('0'=>"assistance",'1'=>1,"12,50 " ),'6'=> array('0'=>"Extension",'1'=>1,"3,00 "));
$count = array();
$i = 0;
foreach ($array as $key=>$arr) {
// Add to the current group count if it exists
if (isset($count[$i][$arr[0]])) {
$count[$i][$arr[0]]++;
}
else $count[$i][$arr[0]] = 1;
$i++;
}
print_r($count);
?>
我有我的主数组:
array(6) {
[1]=> array(3) {
[0]=> string(15) "Extension"
[1]=> int(1)
[2]=> string(6) "3,00 "
}
[2]=> array(3) {
[0]=> string(32) "Physics "
[1]=> string(1) "1"
[2]=> string(6) "3,00 "
}
[3]=> array(3) {
[0]=> string(31) "Physics "
[1]=> int(1)
[2]=> string(6) "6,00 "
}
[4]=> array(3) {
[0]=> string(34) "Desk"
[1]=> int(4)
[2]=> string(8) "127,00 "
}
[5]=> array(3) {
[0]=> string(18) "assistance"
[1]=> int(1)
[2]=> string(7) "12,50 "
}
[6]=> array(3) {
[0]=> string(15) "Extension"
[1]=> int(1)
[2]=> string(6) "3,00 "
}
}
我的预期输出是:
Extension 2
Physics 2
Desk 1
Assistance 1
结果必须在结果数组中 我能怎么做?我尝试使用 array_count_values 函数但不起作用。
我如何购买 answear: 我试过这段代码,但它不起作用
$tabrecap = array();
foreach($counts as $key=>$value){
//echo $key." qte".$value;
$tabrecap = array ($key,$value,$valueOption);
}
只做一个循环并使用每个数组的第一项作为键:
$array = array(
array("Extension", 1, "3,00"),
array("Physics", "1", "3,00"),
array("Physics", 1, "6,00 ")
);
$count = array();
foreach($array as $a)
$count[$a[0]]++;
var_dump($count); // array(2) { ["Extension"]=> int(1) ["Physics"]=> int(2) }
循环就是答案。
<?php
// untested
$counts = Array();
foreach( $array as $subArray ){
$value = $subArray[0];
$counts[ $value ] = ( isset($counts[ $value ]) )
? $counts[ $value ] + 1
: 1;
}
var_dump( $counts);
正如你在评论中所问的,请试试这个:-
<?php
$array = array( '1'=> array('0'=>"Extension", '1'=> 1, '2'=>"3,00 " ), '2'=> array('0'=>"Physics",'1'=>"1","3,00 " ),'3'=> array('0'=>"Physics",'1'=>1,"6,00 "),'4'=> array('0'=>"Desk",'1'=>4,"127,00 "),'5'=> array('0'=>"assistance",'1'=>1,"12,50 " ),'6'=> array('0'=>"Extension",'1'=>1,"3,00 "));
$count = array();
$i = 0;
foreach ($array as $key=>$arr) {
// Add to the current group count if it exists
if (isset($count[$i][$arr[0]])) {
$count[$i][$arr[0]]++;
}
else $count[$i][$arr[0]] = 1;
$i++;
}
print_r($count);
?>