Roblox Studio Lua 循环中的 if 语句

Question

我在这个游戏中有一个 Roblox 游戏，使用 Roblox 开发者网站上的代码更改时间（robloxdev.com）我一直在用两个名为 "open" 和 [=20 的工会制作一扇门=].我希望门在早上 10 点到晚上 5 点之间打开。然而，门打不开，甚至在适当的时候也没有显示 open/close。

这是我当前的代码注意：脚本与两个联合在同一模型（称为：Door）中。

while true do
   if game.Lighting.ClockTime > 10 and game.Lighting.ClockTime < 17 then
        --Open the door
        print("open")
        script.Parent.Closed.Transparency = 1
        script.Parent.Closed.CanCollide = false

        script.Parent.Open.Transparency = 0
        script.Parent.Open.CanCollide = true
    else
        --Close the door
        print("close")
        script.Parent.Closed.Transparency = 0
        script.Parent.Closed.CanCollide = true

        script.Parent.Open.Transparency = 1
        script.Parent.Open.CanCollide = false
    end
end

感谢您的帮助。

Answer 1

您应该在 while 循环中添加等待。

while true do
   if game.Lighting.ClockTime > 10 and game.Lighting.ClockTime < 17 then
        --Open the door
        print("open")
        script.Parent.Closed.Transparency = 1
        script.Parent.Closed.CanCollide = false

        script.Parent.Open.Transparency = 0
        script.Parent.Open.CanCollide = true
    else
        --Close the door
        print("close")
        script.Parent.Closed.Transparency = 0
        script.Parent.Closed.CanCollide = true

        script.Parent.Open.Transparency = 1
        script.Parent.Open.CanCollide = false
    end
    wait(1) -- change this to whatever you want
end

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