当登录尝试超过 3 次时,用户无法使用 spring security Rest API 登录?
when login attempt is exceed more than 3 than user cant to login using spring security Rest API?
我在 java 中使用 spring 安全引导。我有一个覆盖此方法 UserDetails lodUserByUsername(String email)
.
我希望当用户输入错误的电子邮件和密码时提供响应 "Invalid Username and password"
如果他们的电子邮件存在并且他们将输入错误的密码,那么该特定用户的尝试将增加一个并存储到列尝试的数据库中 table。
如果该用户的超出限制超过我想要的响应的 3 个 "Your Username is Blocked"
如果该用户前两次或一次尝试输入错误的密码,则增加唯一的尝试并显示响应 "Your attempt is"+MIN_ATTEMPTS.
如果用户输入了前两次或一次尝试输入错误的密码,然后在他们可以输入正确的用户名和密码之后,则该特定用户的尝试次数设置为 0。
private static final int MAX_ATTEMPTS = 3;
int MIN_ATTEMPTS = 0;
@SneakyThrows
@Override
public UserDetails loadUserByUsername(String email) {
Members members = membersDao.findByEmail(email);
Set<GrantedAuthority> authorities = new HashSet<>();
if (members == null) {
throw new Exception("Invalid username and password");
} else {
MIN_ATTEMPTS = members.getAttempts();
MIN_ATTEMPTS++;
members.setAttempts(MIN_ATTEMPTS);
membersDao.save(members);
}
if (members.getAttempts() <= MAX_ATTEMPTS) {
APIResponseBuilder.build(true , commonMessages.loginSuccess);
return new User(members.getEmail(), members.getPassword(), authorities);
} else {
throw new Exception("You have exceed max +" + MAX_ATTEMPTS + "+limit of login");
}
}
我已将以上代码添加到我的身份验证控制器中,问题已解决
1.controller
private static final int MAX_ATTEMPTS = 3;
@PostMapping("/login")
public ResponseEntity<?> login(@RequestBody LoginMembers loginMembers) throws AuthenticationException, IOException, ServletException {
Members members = membersDao.findByEmail(loginMembers.getEmail());
PasswordEncoder passencoder = new BCryptPasswordEncoder();
if (members == null) {
//Create Error Message for User
throw new RuntimeException("Invalid Username and Password");
}
if (members.getAttempts() >= MAX_ATTEMPTS) {
//Create Error Message for User
throw new RuntimeException("Login Attempt exceeds "+MAX_ATTEMPTS);
}
if (passencoder.matches(loginMembers.getPassword(), members.getPassword())) {
final Authentication authentication = authenticationManager.authenticate(
new UsernamePasswordAuthenticationToken(
loginMembers.getEmail(),
loginMembers.getPassword()
)
);
SecurityContextHolder.getContext().setAuthentication(authentication);
final String token = jwtTokenUtil.generateToken(authentication);
logger.info("You are log in successfully with token");
return ResponseEntity.ok(new AuthTokenRequest(token));
} else {
int attempts = members.getAttempts();
members.setAttempts(++attempts);
membersDao.save(members);
//Create Error Message for User
throw new RuntimeException("Login attempts "+attempts);
}
}
- 方法
@Override
public UserDetails loadUserByUsername(String email) {
Members members = membersDao.findByEmail(email);
Set<GrantedAuthority> authorities = new HashSet<>();
try {
Role role = members.getRoles();
authorities.add(new SimpleGrantedAuthority(role.getRole()));
} catch (Exception e) {
APIResponseBuilder.build(false, e.getMessage(), commonMessages.exception);
}
return new User(members.getEmail(), members.getPassword(), authorities);
}
我在 java 中使用 spring 安全引导。我有一个覆盖此方法 UserDetails lodUserByUsername(String email)
.
我希望当用户输入错误的电子邮件和密码时提供响应 "Invalid Username and password"
如果他们的电子邮件存在并且他们将输入错误的密码,那么该特定用户的尝试将增加一个并存储到列尝试的数据库中 table。
如果该用户的超出限制超过我想要的响应的 3 个 "Your Username is Blocked"
如果该用户前两次或一次尝试输入错误的密码,则增加唯一的尝试并显示响应 "Your attempt is"+MIN_ATTEMPTS.
如果用户输入了前两次或一次尝试输入错误的密码,然后在他们可以输入正确的用户名和密码之后,则该特定用户的尝试次数设置为 0。
private static final int MAX_ATTEMPTS = 3;
int MIN_ATTEMPTS = 0;
@SneakyThrows
@Override
public UserDetails loadUserByUsername(String email) {
Members members = membersDao.findByEmail(email);
Set<GrantedAuthority> authorities = new HashSet<>();
if (members == null) {
throw new Exception("Invalid username and password");
} else {
MIN_ATTEMPTS = members.getAttempts();
MIN_ATTEMPTS++;
members.setAttempts(MIN_ATTEMPTS);
membersDao.save(members);
}
if (members.getAttempts() <= MAX_ATTEMPTS) {
APIResponseBuilder.build(true , commonMessages.loginSuccess);
return new User(members.getEmail(), members.getPassword(), authorities);
} else {
throw new Exception("You have exceed max +" + MAX_ATTEMPTS + "+limit of login");
}
}
我已将以上代码添加到我的身份验证控制器中,问题已解决
1.controller
private static final int MAX_ATTEMPTS = 3;
@PostMapping("/login")
public ResponseEntity<?> login(@RequestBody LoginMembers loginMembers) throws AuthenticationException, IOException, ServletException {
Members members = membersDao.findByEmail(loginMembers.getEmail());
PasswordEncoder passencoder = new BCryptPasswordEncoder();
if (members == null) {
//Create Error Message for User
throw new RuntimeException("Invalid Username and Password");
}
if (members.getAttempts() >= MAX_ATTEMPTS) {
//Create Error Message for User
throw new RuntimeException("Login Attempt exceeds "+MAX_ATTEMPTS);
}
if (passencoder.matches(loginMembers.getPassword(), members.getPassword())) {
final Authentication authentication = authenticationManager.authenticate(
new UsernamePasswordAuthenticationToken(
loginMembers.getEmail(),
loginMembers.getPassword()
)
);
SecurityContextHolder.getContext().setAuthentication(authentication);
final String token = jwtTokenUtil.generateToken(authentication);
logger.info("You are log in successfully with token");
return ResponseEntity.ok(new AuthTokenRequest(token));
} else {
int attempts = members.getAttempts();
members.setAttempts(++attempts);
membersDao.save(members);
//Create Error Message for User
throw new RuntimeException("Login attempts "+attempts);
}
}
- 方法
@Override
public UserDetails loadUserByUsername(String email) {
Members members = membersDao.findByEmail(email);
Set<GrantedAuthority> authorities = new HashSet<>();
try {
Role role = members.getRoles();
authorities.add(new SimpleGrantedAuthority(role.getRole()));
} catch (Exception e) {
APIResponseBuilder.build(false, e.getMessage(), commonMessages.exception);
}
return new User(members.getEmail(), members.getPassword(), authorities);
}