如何创建递增列？

Question

我有 table 这些列名称。

Province/State
Country/Region
Lat
Long
1/22/20
1/23/20
1/24/20
1/25/20
...
...
3/21/20

我知道创建前 4 列，但我不知道如何创建日期列并递增它。

如何一次实现如此多的列？
谢谢！

感染

死亡

恢复

我创建的对象关系数据模型

问题 -: 为您的数据库模式提交有效的 Oracle 脚本。

Answer 1

不要试图每天创建一个专栏；只需创建一个 table 列，其中包含位置、日期和每个统计信息（即感染、恢复、死亡等）的列，然后如果您需要将它们转换为查询（或任何中间层应用程序） [即 PHP、Java、.net] 您正在使用它来访问数据库）。

类似于：

CREATE TABLE Regions(
  id        VARCHAR2(6)
            CONSTRAINT regions__id__pk PRIMARY KEY,
  parent_id VARCHAR2(6)
            CONSTRAINT regions_parent__fk REFERENCES Regions ( id ),
  name      VARCHAR2(50)
            CONSTRAINT regions__name__nn NOT NULL
            CONSTRAINT regions__name__u UNIQUE,
  latitude  NUMBER
            CONSTRAINT regions__lat__nn NOT NULL,
  longitude NUMBER
            CONSTRAINT regions__long__nn NOT NULL,
  CONSTRAINT regions__id__chk CHECK (
       ( parent_id IS     NULL AND REGEXP_LIKE( id, '^[A-Z]{2}$' ) )
    OR ( parent_id IS NOT NULL AND REGEXP_LIKE( id, '^[A-Z]{2}-[A-Z0-9]{1,3}$' ) )
  )
);
COMMENT ON COLUMN Regions.id        IS 'ISO 3166-2 Alpha-2 Country Code or ISO 3166-2 Province Code';
COMMENT ON COLUMN Regions.name      IS 'ISO 3166-2 English Short Name.';
COMMENT ON COLUMN Regions.latitude  IS 'Latitude of the region''s main city.';
COMMENT ON COLUMN Regions.longitude IS 'Longitude of the region''s main city.';

CREATE TABLE Virus_Statistics(
  id        NUMBER(20,0)
            GENERATED ALWAYS AS IDENTITY
            CONSTRAINT virus_statistics__id__pk PRIMARY KEY,
  location  VARCHAR2(6)
            CONSTRAINT virus_statistics__loc__nn NOT NULL
            CONSTRAINT virus_statistics__loc__fk REFERENCES Regions ( id ),
  datetime  DATE
            CONSTRAINT virus_statistics__dt__nn NOT NULL
            CONSTRAINT virus_statistics__dt__chk CHECK ( datetime = TRUNC( datetime ) ),
  infected  NUMBER(10,0),
  recovered NUMBER(10,0),
  dead      NUMBER(10,0),
  CONSTRAINT virus_statistics__loc__dt__u UNIQUE ( location, datetime )
);

然后你就可以输入你的数据了。例如，区域为：

INSERT INTO Regions ( id, parent_id, name, latitude, longitude )
SELECT 'TH',    NULL, 'Thailand',          15.00000,  101.00000 FROM DUAL UNION ALL
SELECT 'JP',    NULL, 'Japan',             36.00000,  138.00000 FROM DUAL UNION ALL
SELECT 'SG',    NULL, 'Singapore',          1.28333,  103.83333 FROM DUAL UNION ALL
SELECT 'NP',    NULL, 'Nepal',             28.16667,   84.25000 FROM DUAL UNION ALL
SELECT 'MY',    NULL, 'Malaysia',           2.50000,  112.50000 FROM DUAL UNION ALL
SELECT 'CA',    NULL, 'Canada',            45.42472, - 75.69500 FROM DUAL UNION ALL
SELECT 'CA-BC', 'CA', 'British Columbia',  48.40733, -123.32977 FROM DUAL;

前 3 列数据为：

INSERT INTO Virus_Statistics ( location, datetime, infected, recovered, dead )
SELECT 'TH',    DATE '2020-01-22', 2 AS i, 0 AS r, 0 AS d FROM DUAL UNION ALL
SELECT 'TH',    DATE '2020-01-23', 3, 0, 0 FROM DUAL UNION ALL
SELECT 'TH',    DATE '2020-01-24', 5, 0, 0 FROM DUAL UNION ALL
SELECT 'JP',    DATE '2020-01-22', 2, 0, 0 FROM DUAL UNION ALL
SELECT 'JP',    DATE '2020-01-23', 1, 0, 0 FROM DUAL UNION ALL
SELECT 'JP',    DATE '2020-01-24', 2, 0, 0 FROM DUAL UNION ALL
SELECT 'SG',    DATE '2020-01-22', 0, 0, 0 FROM DUAL UNION ALL
SELECT 'SG',    DATE '2020-01-23', 1, 0, 0 FROM DUAL UNION ALL
SELECT 'SG',    DATE '2020-01-24', 3, 0, 0 FROM DUAL UNION ALL
SELECT 'NP',    DATE '2020-01-22', 0, 0, 0 FROM DUAL UNION ALL
SELECT 'NP',    DATE '2020-01-23', 0, 0, 0 FROM DUAL UNION ALL
SELECT 'NP',    DATE '2020-01-24', 0, 0, 0 FROM DUAL UNION ALL
SELECT 'MY',    DATE '2020-01-22', 0, 0, 0 FROM DUAL UNION ALL
SELECT 'MY',    DATE '2020-01-23', 0, 0, 0 FROM DUAL UNION ALL
SELECT 'MY',    DATE '2020-01-24', 0, 0, 0 FROM DUAL UNION ALL
SELECT 'CA-BC', DATE '2020-01-22', 0, 0, 0 FROM DUAL UNION ALL
SELECT 'CA-BC', DATE '2020-01-23', 0, 0, 0 FROM DUAL UNION ALL
SELECT 'CA-BC', DATE '2020-01-24', 0, 0, 0 FROM DUAL;

然后，如果您想将其输出为每天的列数，则使用 PIVOT:

SELECT *
FROM   (
  SELECT name,
         latitude,
         longitude,
         datetime,
         infected
  FROM   Virus_Statistics v
         INNER JOIN Regions r
         ON ( r.id = v.location )
)
PIVOT (
  MAX( infected )
  FOR datetime IN (
    DATE '2020-01-22' AS "2020-01-22",
    DATE '2020-01-23' AS "2020-01-23",
    DATE '2020-01-24' AS "2020-01-24"
  )
)

输出：

NAME             | LATITUDE |  LONGITUDE | 2020-01-22 | 2020-01-23 | 2020-01-24
:--------------- | -------: | ---------: | ---------: | ---------: | ---------:
Japan            |       36 |        138 |          2 |          1 |          2
Malaysia         |      2.5 |      112.5 |          0 |          0 |          0
Singapore        |  1.28333 |  103.83333 |          0 |          1 |          3
Nepal            | 28.16667 |      84.25 |          0 |          0 |          0
British Columbia | 48.40733 | -123.32977 |          0 |          0 |          0
Thailand         |       15 |        101 |          2 |          3 |          5

db<>fiddle here

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