使用 Ramda 映射和深层对象

Question

我需要按 "segments" 属性进行过滤，在这种情况下，我需要按段进行过滤：[name: "general]

我有以下数组

const lines = [{
    id: 1191,
    name: "dev",
    segments: []
  },
  {
    id: 1192,
    name: "credit",
    folder: "Embarazadas",
    segments: [{
        "name": "general",
      },
      {
        "name": "custom",
      }
    ]
  },
  {
    id: 1311,
    name: "box",
    segments: [{
      "name": "custom",
      "line_id": 1431,
      "id": 21,
      "active": true
    }]
  },
  {
    id: 2000,
    name: "sin folder",
    folder: null,
    segments: [{
        "name": "custom",
      },
      {
        "name": "general",
      }
    ],
  },
  {
    id: 2000,
    name: "credit card",
    segments: [{
      "name": "general",
    }],
  },
]

我需要获取段为 "general"

的所有对象

我尝试用 Ramda 这样做但我没有得到结果，首先我做了一个线条图，然后是一个过滤器。问题是有时段属性到达空

const filterLinesBySegments = (lines) => {
  const filter = (line) => {
    const hasSegments =R.filter(seg => seg["name"] === "general")(line.segments)
    const newLine = R.compose(
      R.assoc("segments", hasSegments),
    )(line)
    return newLine

  }
  const new= R.map(item => {
      return R.filter(line => {
        return filter(line)
      })(item)

  })(lines)

  return new;
}

Answer 1

要仅保留具有一般段的行，您可以使用 R.filter，并使用 R.where 按特定属性进行过滤。由于 segments 是一个数组，因此使用 R.any 搜索某些对象是否具有 general.

的 name

要从细分中删除自定义，您可以进化对象的细分，并拒绝所有带有 name: custom 的项目。

const { filter, where, any, propEq, reject, evolve, pipe, map } = R

const filterLinesBySegments = filter(where({
  segments: any(propEq('name', 'general'))
}))

const filterCustomFromSegments = evolve({
  segments: reject(propEq('name', 'custom'))
})

const fn = pipe(
  filterLinesBySegments,
  map(filterCustomFromSegments),
)

const lines = [{"id":1191,"name":"dev","segments":[]},{"id":1192,"name":"credit","folder":"Embarazadas","segments":[{"name":"general"},{"name":"custom"}]},{"id":1311,"name":"box","segments":[{"name":"custom","line_id":1431,"id":21,"active":true}]},{"id":2000,"name":"sin folder","folder":null,"segments":[{"name":"custom"},{"name":"general"}]},{"id":2000,"name":"credit card","segments":[{"name":"general"}]}]

const result = fn(lines)

console.log(result)

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使用 Ramda 映射和深层对象

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