删除 php 中出现的字符串

Question

我从 PHP 开始，我尝试删除所有出现的字符串。我的字符串是这样的。

'This is [a test] try [it]'

我想做的是删除所有出现的 [] 和方括号内的文本。

我希望结果类似于：

'This is try'

.

我怎样才能做到这一点？

Answer 1

您可以使用 preg_replace 函数。

preg_replace('~\[[^\]]*\]~', '', $string);

[^\]]* 否定字符 class 匹配任何字符但不匹配右括号 ]，零次或多次。

添加额外的 trim 函数以从结果字符串中删除前导或尾随空格。

$string = 'This is [a test] try [it]';
$result =  preg_replace('~\[[^\]]*\]~', '', $string);
echo trim($result, " ");

Answer 2

你可以试试这个：

$myString = 'This is [a test] try [it]';
$myString = preg_replace('/\[[\w ]+\] */', '', $myString);
var_dump($myString);

解释：

/\[[\w ]+\]/g
 \[ matches the character [ literally
 [\w ]+ match a single character present in the list below
    Quantifier: + Between one and unlimited times, as many times as possible, giving back as needed [greedy]
    \w match any word character [a-zA-Z0-9_]
    ' ' the literal character ' '
 \] matches the character ] literally

删除 php 中出现的字符串

Remove occurrence of string in php

php

string