创建 JSON 并编辑复杂查询 (oracle 11g)

Question

我有 4 个不同的 tables:

table_price_product (contains information related to the products and their price)

table_price_list (contains the information related to the price list)

prices_per_client (contains the information related to the prices for the different clients given a specific product)

clients (contains the information related to the clients)

这是我的 SQL FIDDLE: LINK

我知道了：

CUSTOMER_NUMBER  |  CUSTOMER_CLASS_CODE|    PRICE
(null)           |           A         |    29223
(null)           |           B         |    33223
112121           |           E         |    40340
119435           |           E         |    40340

现在，我想在一次查询中获取与产品和客户相关的所有数据，将 A、B、C 等替换为 CLASS A，CLASS B，CLASS C 分别但是如果 customer_class_code 是 = 'E' 我想从 table clients 最后，转换所有内容并为每个产品获得 JSONs。看看这个，不知何故我需要添加列 "PRICES_FOR_CLIENTS" 和 "groups" 因为我需要这些列来生成 JSON.

SKU     |PRICE|PRICES_FOR_CLIENTS|groups|CLASS A|CLASS B|WALMART|SUPERMARKET
99342435|9999 |                  |      |29223  |33223  |40340  |40340

我想用这些信息生成一个 JSON:

{"sku":"99342435","PRICE":"9999",PRICES_FOR_CLIENTS:[{"group":"CLASS A", "PRICE":"29223"},{"group":"CLASS B", "PRICE":"33223"},{"group":"WALMART","PRICE":"40340"},{"group":"SUPERMARKET", "PRICE":"40340"}]};

你能帮帮我吗？

编辑：

<Item SKU="99342435" Price="9999">
    <PRICES_FOR_CLIENTS>
        <CLIENT_PRICE>
            <Client>WALMART</Client>
            <Price>40340</Price>
            <Site>USSITE</Site>
        </CLIENT_PRICE>
        <CLIENT_PRICE>
            <Client>SUPERMARKET</Client>
            <Price>48343</Price>
            <Site>USSITE</Site>
        </CLIENT_PRICE>
        <CLIENT_PRICE>
            <Client>B</Client>
            <Price>33223</Price>
            <Site>USSITE</Site>
        </CLIENT_PRICE>
        <CLIENT_PRICE>
            <Client>A</Client>
            <Price>29223</Price>
            <Site>USSITE</Site>
        </CLIENT_PRICE>
    </PRICES_FOR_CLIENTS>
</Item>

Answer 1

我认为您可以将大部分代码替换为以下查询。您可能需要调整 IN 子句，如果您经常更改客户列表，这会很痛苦。但这会复制您的结果：

SELECT *
FROM (SELECT DECODE(ppc.customer_class_code, 'E', c.description, ppc.customer_class_code) AS IDENTIFIER, tpp.item_code, tpp.price AS ITEM_PRICE, ppc.price
      FROM table_price_list tpl
      INNER JOIN table_price_product tpp ON tpp.list_header_id = tpl.list_header_id AND tpp.request_id = tpl.request_id
      INNER JOIN prices_per_client ppc ON tpp.item_code = ppc.item_code
      LEFT JOIN clients c ON ppc.customer_number = c.account_number
      WHERE SYSDATE BETWEEN NVL(tpp.start_date_active, SYSDATE) AND NVL(tpp.end_date_active, SYSDATE+1))
PIVOT (AVG(PRICE) FOR IDENTIFIER IN ('A' AS CLASS_A , 'B' AS CLASS_B, 'SUPERMARKET' AS SUPERMARKET, 'WALMART' AS WALMART));

这里有更新 fiddle。

至于 JSON 输出，如果您使用的是更高版本，它会容易得多，因为它现在是核心功能的一部分。

编辑：根据评论添加 XML 功能

您可以查看此查询：

SELECT XMLSERIALIZE(CONTENT
                    XMLELEMENT("Item",
                               XMLATTRIBUTES(sub.item_code AS "SKU", sub.item_price AS "Price"),
                               XMLELEMENT("PRICES_FOR_CLIENTS",
                                          XMLAGG(XMLELEMENT("CLIENT_PRICE",
                                                            XMLFOREST(sub.identifier AS "Client", sub.price AS "Price"))))) AS CLOB INDENT)                                              
FROM (SELECT DECODE(ppc.customer_class_code, 'E', c.description, ppc.customer_class_code) AS IDENTIFIER, tpp.item_code, tpp.price AS ITEM_PRICE, avg(ppc.price) AS PRICE
      FROM table_price_list tpl
      INNER JOIN table_price_product tpp ON tpp.list_header_id = tpl.list_header_id AND tpp.request_id = tpl.request_id
      INNER JOIN prices_per_client ppc ON tpp.item_code = ppc.item_code
      LEFT JOIN clients c ON ppc.customer_number = c.account_number
      WHERE SYSDATE BETWEEN NVL(tpp.start_date_active, SYSDATE) AND NVL(tpp.end_date_active, SYSDATE+1)
      GROUP BY DECODE(ppc.customer_class_code, 'E', c.description, ppc.customer_class_code), tpp.item_code, tpp.price) sub
WHERE sub.identifier IS NOT NULL
GROUP BY sub.item_code, sub.item_price;

这是更新后的 fiddle 查询 (Link)。

产生以下输出：

<Item SKU="99342435" Price="9999">
    <PRICES_FOR_CLIENTS>
        <CLIENT_PRICE>
            <Client>WALMART</Client>
            <Price>40340</Price>
        </CLIENT_PRICE>
        <CLIENT_PRICE>
            <Client>SUPERMARKET</Client>
            <Price>48343</Price>
        </CLIENT_PRICE>
        <CLIENT_PRICE>
            <Client>B</Client>
            <Price>33223</Price>
        </CLIENT_PRICE>
        <CLIENT_PRICE>
            <Client>A</Client>
            <Price>29223</Price>
        </CLIENT_PRICE>
    </PRICES_FOR_CLIENTS>
</Item>

编辑 2：通过字符串连接添加 JSON

以下将通过直接字符串连接输出 JSON：

SELECT '{"sku":"'||sub.item_code||'","PRICE":"'||sub.item_price||'",PRICES_FOR_CLIENTS:['||listagg('{"group":"'||sub.identifier||'","PRICE":"'||sub.price||'"}',',') WITHIN GROUP (ORDER BY sub.identifier)||']};' AS JSON                                              
FROM (SELECT DECODE(ppc.customer_class_code, 'E', c.description, ppc.customer_class_code) AS IDENTIFIER, tpp.item_code, replace(tpp.price, ',', '.') AS ITEM_PRICE, REPLACE(avg(ppc.price), ',', '.') AS PRICE, 
      tpl.request_id, max(tpl.request_id) over (partition by tpp.item_code) as max_request
      FROM table_price_list tpl
      INNER JOIN table_price_product tpp ON tpp.list_header_id = tpl.list_header_id AND tpp.request_id = tpl.request_id
      INNER JOIN prices_per_client ppc ON tpp.item_code = ppc.item_code
      LEFT JOIN clients c ON ppc.customer_number = c.account_number
      WHERE SYSDATE BETWEEN NVL(tpp.start_date_active, SYSDATE) AND NVL(tpp.end_date_active, SYSDATE+1)
      GROUP BY DECODE(ppc.customer_class_code, 'E', c.description, ppc.customer_class_code), tpp.item_code, tpp.price, tpl.request_id) sub 
WHERE sub.identifier IS NOT NULL
and sub.request_id = sub.max_request
GROUP BY sub.item_code, sub.item_price;

并使用此查询更新 fiddle (Link)

编辑 3：添加替换 **编辑 4：添加了分析功能 **

创建 JSON 并编辑复杂查询 (oracle 11g)

Creating JSON and editing a complex query (oracle 11g)

sql

oracle

json

oracle11g