Apache camel 如何以 "body" 格式提交正文

Question

使用 Apache camel，我有 Rest 组件。看起来像：

    <post uri="/body" method="POST">
        <description>Here is post method</description>
        <param name="save" type="body" dataType="string"/>
        <route>
            <process ref="postRedirectProcessor" />
            <to uri="direct:commonRoute" />
        </route>
    </post>

并且此端点处理这样的精细请求：

curl -i --data "b=hereisbody" http://localhost:8080/body (works fine, but I don't need it)

（我可以看到它进入 postRedirectProcessor，这很好）。但这不是我想要的。我希望它处理这样的请求：

curl -i --data "hereisbody" http://localhost:8080/body (doesn't work, causes 405)

我的意思是，"data" 的格式是 而不是 ，就像 k=v&k2=v2，但它只是字符串，就像在示例中一样（例如 --data "something"）。

它会导致异常，不会进入 postRedirectProcessor。

2020-04-10 18:43:09,716 ERROR [http-nio-8080-exec-6] - ,,, - Servlet.service() for servlet [CamelServlet] in context with path [] threw exception
java.lang.IllegalArgumentException: Invalid parameter, expected to be a pair but was hereisbody
    at org.apache.camel.http.common.DefaultHttpBinding.readFormUrlEncodedBody(DefaultHttpBinding.java:272) ~[camel-http-common-2.24.3.jar:2.24.3]
    at org.apache.camel.http.common.DefaultHttpBinding.readRequest(DefaultHttpBinding.java:116) ~[camel-http-common-2.24.3.jar:2.24.3]
    at org.apache.camel.http.common.HttpMessage.<init>(HttpMessage.java:56) ~[camel-http-common-2.24.3.jar:2.24.3]
    at org.apache.camel.http.common.CamelServlet.doService(CamelServlet.java:187) ~[camel-http-common-2.24.3.jar:2.24.3]
    at org.apache.camel.http.common.CamelServlet.service(CamelServlet.java:79) ~[camel-http-common-2.24.3.jar:2.24.3]
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:741) ~[tomcat-embed-core-9.0.31.jar:9.0.31]
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:231) ~[tomcat-embed-core-9.0.31.jar:9.0.31]

我想，param type="body" 就像 xml 发布的那样，可以解决问题，但运气不好。

Answer 1

Curl 默认在 --data 和 Content-Type: application/x-www-form-urlencoded header 中发送数据。参见 How to post raw body data with curl?

x-www-form-urlencoded 必须采用 key/value 格式 (specification)。这就是抛出异常的原因。

The name is separated from the value by = and name/value pairs are separated from each other by &.

要发送原始数据，您需要指定另一个 Content-Type。

curl -v -i -H "Content-Type: text/plain" --data "hereisbody" http://localhost:8080/body

Apache camel 如何以 "body" 格式提交正文

Apache camel how to submit body in "body" format

java

rest

http

apache-camel