MySQL

Question

尝试 LEFT JOIN table 与部分字符串匹配。我已经尝试更改 LIKE 条件中的通配符，但它仍然只搜索完整的字符串。有什么建议么？我有一个存储在 table 中的产品缩写列表。使用部分匹配比必须拼出每个产品更容易管理此列表。

提前致谢！

CREATE TABLE `order`
(
  order_id INT (11) NOT NULL,
  shipping_firstname VARCHAR (128) NOT NULL,
  shipping_lastname VARCHAR (128) NOT NULL
  );

CREATE TABLE order_option
(
  order_id integer NOT NULL,
  order_product_id INT (11) NOT NULL,
  `value` VARCHAR (10) NOT NULL
);

CREATE TABLE order_product
(
  order_id INTEGER NOT NULL,
  quantity INT (11) NOT NULL,
  order_product_id INT (11) NOT NULL,
  name VARCHAR (55) NOT NULL
);

CREATE TABLE product_abbreviations
(
  product_name VARCHAR (128) NOT NULL,
  product_abbr VARCHAR (55) NOT NULL
);

INSERT `order`
  (order_id, shipping_firstname, shipping_lastname)
VALUES
  (12345, 'Mason', 'Sklut'),
  (12346, 'John', 'Doe');

INSERT order_option
  (order_id, order_product_id, `value`)
VALUES
  (12345, 101, 'Large'),
  (12345, 101, 'Red'),
  (12346, 102, 'Small'),
  (12346, 102, 'Blue');

INSERT order_product
  (order_id, quantity, order_product_id, name)
VALUES
  (12345, 1, 101, 'T-shirt for Halloween'),
  (12345, 2, 101, 'T-shirt for Spring Break'),
  (12346, 5, 102, 'T-shirt for Pacific West');


INSERT product_abbreviations
  (product_name, product_abbr)
VALUES
  ('T-shirt for', 'Tee'),
  ('Halloween', 'Hallo'),
  ('Spring Break', 'SB'),
  ('Pacific West', 'PW');

LEFT JOIN `product_abbreviations` AS `pa` ON `pa`.`product_name` LIKE CONCAT('%',`op`.`name`,'%')

在此处查看完整查询：
https://dbfiddle.uk/?rdbms=mysql_5.6&fiddle=536e2f367cebc053e95709ec7d90a7aa

预期输出：

Order ID  | Name        | Qty | Option | Size | Product    | Ref
----------------------------------------------------------------------------
12345     | Mason Sklut | 1   | R      | L    | Tee Hallo  | R / Tee Hallo L
12345     | Mason Sklut | 2   | R      | L    | Tee SB     | 2x R / Tee SB L
12346     | John Doe    | 5   | Bl     | S    | Tee PW     | 5x Bl / Tee PW S

Answer 1

我认为您希望模式以相反的方式匹配。即产品名称中应包含产品简称：

LEFT JOIN `product_abbreviations` AS `pa` 
    ON `op`.`name` LIKE CONCAT('%', `pa`.`product_name` ,'%')

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