从 2 个表和其他 table 中获取每个最新数据
get the each lastest data from 2 tabel and data from other table
0
我有这样的数据：
table_a
ID CREATED_DATE PRODUCT
-----------------------------------------------
AA 2017-05-19 02:00:00 PHONE
BB 2017-05-19 02:00:00 CAMERA
CC 2017-05-19 02:00:00 TELIVISION
table_b
ID TRANS_ID CREATED_DATE STATUS_ORDER
---------------------------------------------------
1 AA 2017-05-19 02:00:00 WAITING
2 AA 2017-05-20 02:00:00 IN_PROCESS
3 BB 2017-05-19 02:00:00 WAITING
4 CC 2017-05-19 02:00:00 WAITING
5 CC 2017-05-20 02:00:00 CANCELLED
table_c
ID TRANS_ID CREATED_DATE STATUS_PAYMENT
-----------------------------------------------------
1 BB 2017-05-19 02:00:00 WAITING
table_d
ID TRANS_ID CREATED_DATE STATUS_CONTRACT
-------------------------------------------------------
1 AA 2017-05-19 02:00:00 IN_PROCESS
2 AA 2017-05-20 02:00:00 APPROVED
4 CC 2017-05-19 02:00:00 IN_PROCESS
5 CC 2017-05-20 02:00:00 REJECT
我想在 table 视图中显示数据，如下所示：
ID CREATED_DATE STATUS_ORDER STATUS_PAYMENT STATUS_CONTRACT
--------------------------------------------------------------------------------------------
AA 2017-05-19 02:00:00 IN_PROCESS NULL APPROVED
BB 2017-05-19 02:00:00 WAITING WAITING NULL
CC 2017-05-19 02:00:00 CANCELLED NULL REJECT
我从 table_b 和 table_d 中获取每个 trans_id 的最新数据并且我 运行 这个查询但是它不能从 table_c，因为 trans_id 在 table_d
上不存在
SELECT
a.id,
a.created_date,
b.status_order,
c.status_payment,
d.status_contract
FROM
table_a a
INNER JOIN table_b b ON a.id = b.trans_id
LEFT OUTER JOIN table_c c ON a.id = c.trans_id
LEFT OUTER JOIN table_c d ON a.id = d.trans_id
WHERE
b.created_date = (
SELECT
MAX(e.created_date)
FROM
table_b e
WHERE
b.trans_id = e.trans_id
)
AND
d.created_date = (
SELECT
MAX(f.created_date)
FROM
table_d f
WHERE
f.trans_id = d.trans_id
)
结果变为：
ID CREATED_DATE STATUS_ORDER STATUS_PAYMENT STATUS_CONTRACT
------------------------------------------------------------------------------
AA 2017-05-19 02:00:00 IN_PROCESS NULL APPROVED
CC 2017-05-19 02:00:00 CANCELLED NULL REJECT
不符合预期
这样的事情怎么样？关注代码中的注释。示例数据从第 1 行到第 22 行，因此您需要的代码从第 23 行开始。
SQL> with
2 -- sample data
3 table_a(id, created_date, product) as
4 (select 'aa', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'phone' from dual union all
5 select 'bb', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'camera' from dual union all
6 select 'cc', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'television' from dual
7 ),
8 table_b (id, trans_id, created_date, status_order) as
9 (select 1, 'aa', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'waiting' from dual union all
10 select 2, 'aa', to_date('20.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'in_process' from dual union all
11 select 3, 'bb', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'waiting' from dual union all
12 select 4, 'cc', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'waiting' from dual union all
13 select 5, 'cc', to_date('20.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'cancelled' from dual
14 ),
15 table_c (id, trans_id, created_Date, status_payment) as
16 (select 1, 'bb', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'waiting' from dual),
17 table_d (id, trans_id, created_date, status_contract) as
18 (select 1, 'aa', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'in_process' from dual union all
19 select 2, 'aa', to_date('20.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'approved' from dual union all
20 select 3, 'cc', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'in_process' from dual union all
21 select 4, 'cc', to_date('20.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'reject' from dual
22 ),
23 uni as
24 -- union a+b+c to have everything in the same "table" (CTE)
25 (select id trans_id, created_date, null status_order, null status_payment
26 from table_a
27 union all
28 select trans_id, created_date, status_order, null status_payment
29 from table_b
30 union all
31 select trans_id, created_date, null status_order, status_payment
32 from table_c
33 ),
34 latest as
35 -- latest date per TRANS_ID
36 (select trans_id,
37 max(created_date) created_date
38 from uni
39 group by trans_id
40 )
41 -- final query
42 select l.trans_id,
43 l.created_date,
44 max(u.status_order) status_order,
45 max(u.status_payment) status_payment,
46 max(d.status_contract) status_contract
47 from latest l
48 join uni u on u.trans_id = l.trans_id and u.created_date = l.created_date
49 left join table_d d on d.trans_id = l.trans_id and d.created_date = l.created_date
50 group by l.trans_id, l.created_Date
51 order by l.trans_id, l.created_Date;
TR CREATED_DATE STATUS_ORDER STATUS_PAYMENT STATUS_CONTRACT
-- ---------------- --------------- --------------- ---------------
aa 2017-05-20 02:00 in_process approved
bb 2017-05-19 02:00 waiting waiting
cc 2017-05-20 02:00 cancelled reject
SQL>
您可以在 oracle 18c DB 上找到具有所需输出的完整解决方案 fiddle link :https://dbfiddle.uk/?rdbms=oracle_18&fiddle=3f3de8149268cfef58fe7be28106ab3a
我使用 https://dbfiddle.uk/ 上提供的数据创建了数据模型，并通过查询和所需的输出解决了问题。
查询如下：
SELECT
a.id,
a.created_date,
b.status_order,
c.status_payment,
d.status_contract
FROM table_a a,
(SELECT trans_id,STATUS_order
FROM (SELECT trans_id,STATUS_order,row_number() OVER (PARTITION BY trans_id ORDER BY created_date DESC) rn
FROM table_b)
WHERE rn = 1) b,
(SELECT trans_id,STATUS_PAYMENT
FROM (SELECT trans_id,STATUS_PAYMENT,row_number() OVER (PARTITION BY trans_id ORDER BY created_date DESC) rn
FROM table_c)
WHERE rn = 1) c,
(SELECT trans_id,status_contract
FROM (SELECT trans_id,status_contract,row_number() OVER (PARTITION BY trans_id ORDER BY created_date DESC) rn
FROM table_d)
WHERE rn =1) d
WHERE a.id = b.trans_id(+)
AND a.id = c.trans_id(+)
AND a.id = d.trans_id(+);
输出：
ID CREATED_DATE STATUS_ORDER STATUS_PAYMENT STATUS_CONTRACT
AA 2017-05-19 02:00:00 IN_PROCESS APPROVED
BB 2017-05-19 02:00:00 WAITING WAITING
CC 2017-05-19 02:00:00 CANCELLED REJECT
0
我有这样的数据：
table_a
ID CREATED_DATE PRODUCT
-----------------------------------------------
AA 2017-05-19 02:00:00 PHONE
BB 2017-05-19 02:00:00 CAMERA
CC 2017-05-19 02:00:00 TELIVISION
table_b
ID TRANS_ID CREATED_DATE STATUS_ORDER
---------------------------------------------------
1 AA 2017-05-19 02:00:00 WAITING
2 AA 2017-05-20 02:00:00 IN_PROCESS
3 BB 2017-05-19 02:00:00 WAITING
4 CC 2017-05-19 02:00:00 WAITING
5 CC 2017-05-20 02:00:00 CANCELLED
table_c
ID TRANS_ID CREATED_DATE STATUS_PAYMENT
-----------------------------------------------------
1 BB 2017-05-19 02:00:00 WAITING
table_d
ID TRANS_ID CREATED_DATE STATUS_CONTRACT
-------------------------------------------------------
1 AA 2017-05-19 02:00:00 IN_PROCESS
2 AA 2017-05-20 02:00:00 APPROVED
4 CC 2017-05-19 02:00:00 IN_PROCESS
5 CC 2017-05-20 02:00:00 REJECT
我想在 table 视图中显示数据，如下所示：
ID CREATED_DATE STATUS_ORDER STATUS_PAYMENT STATUS_CONTRACT
--------------------------------------------------------------------------------------------
AA 2017-05-19 02:00:00 IN_PROCESS NULL APPROVED
BB 2017-05-19 02:00:00 WAITING WAITING NULL
CC 2017-05-19 02:00:00 CANCELLED NULL REJECT
我从 table_b 和 table_d 中获取每个 trans_id 的最新数据并且我 运行 这个查询但是它不能从 table_c，因为 trans_id 在 table_d
上不存在SELECT
a.id,
a.created_date,
b.status_order,
c.status_payment,
d.status_contract
FROM
table_a a
INNER JOIN table_b b ON a.id = b.trans_id
LEFT OUTER JOIN table_c c ON a.id = c.trans_id
LEFT OUTER JOIN table_c d ON a.id = d.trans_id
WHERE
b.created_date = (
SELECT
MAX(e.created_date)
FROM
table_b e
WHERE
b.trans_id = e.trans_id
)
AND
d.created_date = (
SELECT
MAX(f.created_date)
FROM
table_d f
WHERE
f.trans_id = d.trans_id
)
结果变为：
ID CREATED_DATE STATUS_ORDER STATUS_PAYMENT STATUS_CONTRACT
------------------------------------------------------------------------------
AA 2017-05-19 02:00:00 IN_PROCESS NULL APPROVED
CC 2017-05-19 02:00:00 CANCELLED NULL REJECT
不符合预期
这样的事情怎么样？关注代码中的注释。示例数据从第 1 行到第 22 行，因此您需要的代码从第 23 行开始。
SQL> with
2 -- sample data
3 table_a(id, created_date, product) as
4 (select 'aa', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'phone' from dual union all
5 select 'bb', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'camera' from dual union all
6 select 'cc', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'television' from dual
7 ),
8 table_b (id, trans_id, created_date, status_order) as
9 (select 1, 'aa', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'waiting' from dual union all
10 select 2, 'aa', to_date('20.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'in_process' from dual union all
11 select 3, 'bb', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'waiting' from dual union all
12 select 4, 'cc', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'waiting' from dual union all
13 select 5, 'cc', to_date('20.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'cancelled' from dual
14 ),
15 table_c (id, trans_id, created_Date, status_payment) as
16 (select 1, 'bb', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'waiting' from dual),
17 table_d (id, trans_id, created_date, status_contract) as
18 (select 1, 'aa', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'in_process' from dual union all
19 select 2, 'aa', to_date('20.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'approved' from dual union all
20 select 3, 'cc', to_date('19.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'in_process' from dual union all
21 select 4, 'cc', to_date('20.05.2017 02:00', 'dd.mm.yyyy hh24:mi'), 'reject' from dual
22 ),
23 uni as
24 -- union a+b+c to have everything in the same "table" (CTE)
25 (select id trans_id, created_date, null status_order, null status_payment
26 from table_a
27 union all
28 select trans_id, created_date, status_order, null status_payment
29 from table_b
30 union all
31 select trans_id, created_date, null status_order, status_payment
32 from table_c
33 ),
34 latest as
35 -- latest date per TRANS_ID
36 (select trans_id,
37 max(created_date) created_date
38 from uni
39 group by trans_id
40 )
41 -- final query
42 select l.trans_id,
43 l.created_date,
44 max(u.status_order) status_order,
45 max(u.status_payment) status_payment,
46 max(d.status_contract) status_contract
47 from latest l
48 join uni u on u.trans_id = l.trans_id and u.created_date = l.created_date
49 left join table_d d on d.trans_id = l.trans_id and d.created_date = l.created_date
50 group by l.trans_id, l.created_Date
51 order by l.trans_id, l.created_Date;
TR CREATED_DATE STATUS_ORDER STATUS_PAYMENT STATUS_CONTRACT
-- ---------------- --------------- --------------- ---------------
aa 2017-05-20 02:00 in_process approved
bb 2017-05-19 02:00 waiting waiting
cc 2017-05-20 02:00 cancelled reject
SQL>
您可以在 oracle 18c DB 上找到具有所需输出的完整解决方案 fiddle link :https://dbfiddle.uk/?rdbms=oracle_18&fiddle=3f3de8149268cfef58fe7be28106ab3a 我使用 https://dbfiddle.uk/ 上提供的数据创建了数据模型，并通过查询和所需的输出解决了问题。
查询如下：
SELECT
a.id,
a.created_date,
b.status_order,
c.status_payment,
d.status_contract
FROM table_a a,
(SELECT trans_id,STATUS_order
FROM (SELECT trans_id,STATUS_order,row_number() OVER (PARTITION BY trans_id ORDER BY created_date DESC) rn
FROM table_b)
WHERE rn = 1) b,
(SELECT trans_id,STATUS_PAYMENT
FROM (SELECT trans_id,STATUS_PAYMENT,row_number() OVER (PARTITION BY trans_id ORDER BY created_date DESC) rn
FROM table_c)
WHERE rn = 1) c,
(SELECT trans_id,status_contract
FROM (SELECT trans_id,status_contract,row_number() OVER (PARTITION BY trans_id ORDER BY created_date DESC) rn
FROM table_d)
WHERE rn =1) d
WHERE a.id = b.trans_id(+)
AND a.id = c.trans_id(+)
AND a.id = d.trans_id(+);
输出：
ID CREATED_DATE STATUS_ORDER STATUS_PAYMENT STATUS_CONTRACT
AA 2017-05-19 02:00:00 IN_PROCESS APPROVED
BB 2017-05-19 02:00:00 WAITING WAITING
CC 2017-05-19 02:00:00 CANCELLED REJECT