如何增加或减少数组中某项被选中的概率?

How to increase or decrease the probability of an item of an array being picked?

所以,假设我正在制作老虎机之类的东西,要使用我想使用的表情符号,我会在数组中定义它们。

var arr = ["emoji","emoji2","emoji3","emoji4","emoji5"]

假设我希望表情符号 1 - 4 出现的次数多于 5,并说要降低表情符号 5 被选中的概率。

我可以做一些大事,例如:

var arr = [
"emoji","emoji2","emoji3","emoji4",
"emoji","emoji2","emoji3","emoji4",
"emoji","emoji2","emoji3","emoji4",
"emoji","emoji2","emoji3","emoji4",
"emoji","emoji2","emoji3","emoji4",
"emoji","emoji2","emoji3","emoji4","emoji5",
]
var emoji = arr[Math.floor(Math.random() * arr.length)]

但这不是一个非常有效的想法,那么是否可以在不制作非常大的数组的情况下实现上述想法?

我的目标基本上是拥有一个像

这样的数组
var arr = ["emoji","emoji2","emoji3","emoji4","emoji5"]

它会输出一些表情符号 1 - 4 比表情符号 5 更频繁出现的东西,没有大数组。

这样试试

var arr = ["emoji","emoji2","emoji3","emoji4","emoji5"]
var emoji = arr[Math.floor(Math.random() * (Math.random() < 0.75 ? arr.length - 1 : arr.length))]

对于加权概率的一般情况,一种选择是拥有一个其键为累积概率的对象。假设您希望 emoji5 在 4% 的时间内出现 - 那么,累积概率将为 24、48、72、96、100(其中最后一个区间 96 到 100 表示 emoji5 的权重较低)。然后生成一个1-100之间的随机数,并找到第一个大于所选数字的密钥:

const probs = {
  24: "emoji",
  48: "emoji2",
  72: "emoji3",
  96: "emoji4",
  100: "emoji5"
};

const keys = Object.keys(probs).map(Number);
const generate = () => {
  const rand = Math.floor(Math.random() * 100);
  const key = keys.find(key => rand < key);
  return probs[key];
};
for (let i = 0; i < 10; i++) {
  console.log(generate());
}

另一种选择是给每个字符串关联一个weight数字,并给emoji5一个低的数字,将权重相加,生成一个介于0和总权重之间的随机数,并找到第一个匹配项:

const weights = [
  [4, 'emoji'],
  [4, 'emoji2'],
  [4, 'emoji3'],
  [4, 'emoji4'],
  [1, 'emoji5'],
];

const totalWeight = weights.reduce((a, [weight]) => a + weight, 0);
const weightObj = {};
let weightUsed = 0;
for (const item of weights) {
  weightUsed += item[0];
  weightObj[weightUsed] = item;
}
const keys = Object.keys(weightObj);
const generate = () => {
  const rand = Math.floor(Math.random() * totalWeight);
  const key = keys.find(key => rand < key);
  return weightObj[key][1];
};
for (let i = 0; i < 10; i++) {
  console.log(generate());
}