如何将 echo 语句和 arp 语句的输出放在一行中?
How to place the output of an echo statement and an arp statement on one line?
如何在一行中获得输出 "echo" 和 "macaddress"?
这就是我得到的:
ipRange="192.168.0."
macaddress= arp | grep -w "$ipRange" | awk '{print ,}'
ping -c1 "$ipRange" > /dev/null
if [ $? -eq 0 ]; then
echo "deze host met mac address en ip address is up $macaddress"
else
echo "het is down"
fi
这是输出:
VirtualBox ~ $ bash test2.sh 149
e0:b9:a5:f8:24:c3 192.168.0.149
deze host met mac address en ip address is up
只需替换macaddress= arp | grep -w "$ipRange" | awk '{print ,}'
和macaddress=$(arp | grep -w "$ipRange" | awk '{print ,}')
这应该在单行输出
ipRange="192.168.0."
macaddress=$(arp | grep -w "$ipRange" | awk '{print ,}')
ping -c1 "$ipRange" > /dev/null
if [ $? -eq 0 ]; then
echo "deze host met mac address en ip address is up $macaddress"
else
echo "het is down"
fi
如何在一行中获得输出 "echo" 和 "macaddress"? 这就是我得到的:
ipRange="192.168.0."
macaddress= arp | grep -w "$ipRange" | awk '{print ,}'
ping -c1 "$ipRange" > /dev/null
if [ $? -eq 0 ]; then
echo "deze host met mac address en ip address is up $macaddress"
else
echo "het is down"
fi
这是输出:
VirtualBox ~ $ bash test2.sh 149
e0:b9:a5:f8:24:c3 192.168.0.149
deze host met mac address en ip address is up
只需替换macaddress= arp | grep -w "$ipRange" | awk '{print ,}'
和macaddress=$(arp | grep -w "$ipRange" | awk '{print ,}')
这应该在单行输出
ipRange="192.168.0."
macaddress=$(arp | grep -w "$ipRange" | awk '{print ,}')
ping -c1 "$ipRange" > /dev/null
if [ $? -eq 0 ]; then
echo "deze host met mac address en ip address is up $macaddress"
else
echo "het is down"
fi