DuplicateMappingException Table [] contains physical column name [] 被多个逻辑列名引用:[_id], [Id]
DuplicateMappingException Table [] contains physical column name [] referred to by multiple logical column names: [_id], [Id]
我正在重写一个项目,但遇到构建问题。
Caused by: org.hibernate.DuplicateMappingException: Table [language] contains physical column name [person_id] referred to by multiple logical column names: [person_id], [personId]
哪里
@Builder
@Data
@AllArgsConstructor
@NoArgsConstructor
@Entity
@IdClass(LanguagePK.class)
@Table(name = "language")
public class Language {
@Id
@Column(name = "person_id")
private int personId;
@Id
@Column(name = "position")
private int position;
@Id
@Column(name = "language_name")
private String languageNameVal;
@Column(name = "language_level")
private String languageLevelVal;
@ManyToOne
@JoinColumn(name = "person_id", referencedColumnName = "id", nullable = false, insertable = false,updatable = false)
@JsonBackReference(value = "languages")
private Person person;
@ManyToOne
@JoinColumn(name = "language_name", referencedColumnName = "name", nullable = false, insertable = false,updatable = false)
@JsonIgnore
private LanguageName languageName;
@ManyToOne
@JoinColumn(name = "language_level", referencedColumnName = "level", nullable = false, insertable = false,updatable = false)
@JsonIgnore
private LanguageLevel languageLevel;
}
和
@Builder
@Data
@NoArgsConstructor
@AllArgsConstructor
@Entity
@Table(name = "person")
public class Person implements Serializable{
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private int id;
@JsonManagedReference(value = "languages")
@OneToMany(mappedBy = "person", cascade = {CascadeType.PERSIST, CascadeType.MERGE})
private Set<Language> languages;
我用
- 休眠 v.5.4.13.Final
- spring-boot v. 2.2.5.RELEASE
- gradle
- java 1.8
- 龙目岛
变化非常小,就像我之前使用 maven、用于休眠的 SessionFactory、传统的 getter 和 setter。
我看到一些类似的问题,其中 NamingStrategy 在 hibernate 4 和 5 之间迁移期间出现问题,但此代码适用于 hiberante 为 5.4 的第一个项目。10.Final。
我喜欢 IdClass,因为我可以访问 personId 作为原始值,而不必从对象 person 加载数据。
我在没有 insertable = false,updatable = false
的情况下看到了类似的问题,但我遇到了...
发现类似问题 here
解决方法
问题出在访问策略字段与 属性 访问之间。
在之前的项目中,一切都是基于 属性 的访问,但是在我添加了 lombok 之后,class Language
是基于字段的访问。
class LanguagePK
是
public class LanguagePK implements Serializable {
private static final long serialVersionUID = 1L;
private int personId;
private int position;
private String languageNameVal;
@Column(name = "person_id")
@Id
public int getPersonId() {
return personId;
}
public void setPersonId(int personId) {
this.personId = personId;
}
@Column(name = "position")
@Id
public int getPosition() {
return position;
}
public void setPosition(int position) {
this.position = position;
}
@Column(name = "language_name")
@Id
public String getLanguageNameVal() {
return languageNameVal;
}
public void setLanguageNameVal(String languageNameVal) {
this.languageNameVal = languageNameVal;
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
LanguagePK that = (LanguagePK) o;
if (personId != that.personId) return false;
if (position != that.position) return false;
if (languageNameVal != null ? !languageNameVal.equals(that.languageNameVal) : that.languageNameVal != null)
return false;
return true;
}
@Override
public int hashCode() {
int result = personId;
result = 31 * result + position;
result = 31 * result + (languageNameVal != null ? languageNameVal.hashCode() : 0);
return result;
}
}
够用了
@EqualsAndHashCode
public class EducationPK implements Serializable {
private int personId;
private int position;
}
我正在重写一个项目,但遇到构建问题。
Caused by: org.hibernate.DuplicateMappingException: Table [language] contains physical column name [person_id] referred to by multiple logical column names: [person_id], [personId]
哪里
@Builder
@Data
@AllArgsConstructor
@NoArgsConstructor
@Entity
@IdClass(LanguagePK.class)
@Table(name = "language")
public class Language {
@Id
@Column(name = "person_id")
private int personId;
@Id
@Column(name = "position")
private int position;
@Id
@Column(name = "language_name")
private String languageNameVal;
@Column(name = "language_level")
private String languageLevelVal;
@ManyToOne
@JoinColumn(name = "person_id", referencedColumnName = "id", nullable = false, insertable = false,updatable = false)
@JsonBackReference(value = "languages")
private Person person;
@ManyToOne
@JoinColumn(name = "language_name", referencedColumnName = "name", nullable = false, insertable = false,updatable = false)
@JsonIgnore
private LanguageName languageName;
@ManyToOne
@JoinColumn(name = "language_level", referencedColumnName = "level", nullable = false, insertable = false,updatable = false)
@JsonIgnore
private LanguageLevel languageLevel;
}
和
@Builder
@Data
@NoArgsConstructor
@AllArgsConstructor
@Entity
@Table(name = "person")
public class Person implements Serializable{
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private int id;
@JsonManagedReference(value = "languages")
@OneToMany(mappedBy = "person", cascade = {CascadeType.PERSIST, CascadeType.MERGE})
private Set<Language> languages;
我用
- 休眠 v.5.4.13.Final
- spring-boot v. 2.2.5.RELEASE
- gradle
- java 1.8
- 龙目岛
变化非常小,就像我之前使用 maven、用于休眠的 SessionFactory、传统的 getter 和 setter。
我看到一些类似的问题,其中 NamingStrategy 在 hibernate 4 和 5 之间迁移期间出现问题,但此代码适用于 hiberante 为 5.4 的第一个项目。10.Final。
我喜欢 IdClass,因为我可以访问 personId 作为原始值,而不必从对象 person 加载数据。
我在没有 insertable = false,updatable = false
的情况下看到了类似的问题,但我遇到了...
发现类似问题 here
解决方法
问题出在访问策略字段与 属性 访问之间。
在之前的项目中,一切都是基于 属性 的访问,但是在我添加了 lombok 之后,class Language
是基于字段的访问。
class LanguagePK
是
public class LanguagePK implements Serializable {
private static final long serialVersionUID = 1L;
private int personId;
private int position;
private String languageNameVal;
@Column(name = "person_id")
@Id
public int getPersonId() {
return personId;
}
public void setPersonId(int personId) {
this.personId = personId;
}
@Column(name = "position")
@Id
public int getPosition() {
return position;
}
public void setPosition(int position) {
this.position = position;
}
@Column(name = "language_name")
@Id
public String getLanguageNameVal() {
return languageNameVal;
}
public void setLanguageNameVal(String languageNameVal) {
this.languageNameVal = languageNameVal;
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
LanguagePK that = (LanguagePK) o;
if (personId != that.personId) return false;
if (position != that.position) return false;
if (languageNameVal != null ? !languageNameVal.equals(that.languageNameVal) : that.languageNameVal != null)
return false;
return true;
}
@Override
public int hashCode() {
int result = personId;
result = 31 * result + position;
result = 31 * result + (languageNameVal != null ? languageNameVal.hashCode() : 0);
return result;
}
}
够用了
@EqualsAndHashCode
public class EducationPK implements Serializable {
private int personId;
private int position;
}