尝试 select 通过匹配行值来匹配列，但 return 该列中另一行的值

Question

我有一个 pandas 数据框

       field          sev         iso         des 
0  shortname          sev         iso         des 
1   fullname  Sevoflurane  Isoflurane  Desflurane
2        id             0           1           2
3 colorname          Gold Dark Magenta Royal Blue
4  colorHex       #FFD700     #8B008B     #4169E1
5       mac           2.1        1.15         5.8

我正在尝试找到正确的 pandas 语法来搜索 'id' 行匹配值 1 和 return 相同列 'mac' 值

如果可以select列

c = df.loc['id'] = 1

现在我尝试获取无效的列 'mac' 值

_mac = csv_rx_df.at[c, 'mac']

我该怎么做？

Answer 1

#set 'field' as index
df = df.set_index('field')
#get the column where id row equals "1", and subsequently,
#get the value for 'mac'
df.loc['mac',df.loc['id',:].eq("1")]

iso    1.15
Name: mac, dtype: object

尝试 select 通过匹配行值来匹配列，但 return 该列中另一行的值

Trying to select a column by matching a row value but return the value of another row in that column

python

lookup

dataframe

pandas

jupyter