Notepad++ 正则表达式将文件中的日期放在每行的开头

Question

给定以下格式的文件（其中 X 是任何文本，没有换行符）：

01st December 2019
0100 X
0200 X
0300 X
1745 X
02nd December 2019
0015 X
1555 X
2335 X

将正则表达式转换为将日期放在每行的开头，并删除仅包含日期的行，例如：

01st December 2019 0100 X
01st December 2019 0200 X
01st December 2019 0300 X
01st December 2019 1745 X
02nd December 2019 0015 X
02nd December 2019 1555 X
02nd December 2019 2335 X

我知道我可以通过搜索 [0-3][0-9][snrt[tdh] 找到以日期开头的行，通过搜索 ^ 可以找到以日期开头的行，但我怎么能说 "find ^ and replace with the previous match for the date" ？

Answer 1

如果加入的行数不是太多，你可以按照下面的方法，我把行数限制在7行：

Ctrl+H
查找内容：^(\d\d(?:st|nd|rd|th) \w+ \d{4})$\R(^\d{4} .+$)(?:\R(^\d{4} .+$))?(?:\R(^\d{4} .+$))?(?:\R(^\d{4} .+$))?(?:\R(^\d{4} .+$))?(?:\R(^\d{4} .+$))?
替换为： (?3\n )(?4\n )(?5\n )(?6\n )(?7\n )
检查环绕
检查 正则表达式
取消选中 . matches newline
全部替换

解释：

^                       # beginning of line
  (                     # group 1
    \d\d                  # 2 digits (the day)
    (?:st|nd|rd|th)       # any of st or nd or rd or th
    \w+                   # 1 or more word character (the month)
    \d{4}                 # 4 digits (the year)
  )                     # end group
$                       # end of line
\R                      # any kind of linebreak
(                       # group 2
  ^                     # beginning of line
    \d{4}                 # 4 digits (the time)
    .+                    # 1 or more any character but newline
  $                     # end of line
)                       # end group 2
(?:                     # non capture group
  \R                      # any kind of linebreak
  (^\d{4} .+$)            # group 3, same pattern as in group 2
)?                      # end group, optional
(?:\R(^\d{4} .+$))?     # same as above for group 4
(?:\R(^\d{4} .+$))?     # same as above for group 5
(?:\R(^\d{4} .+$))?     # same as above for group 6
(?:\R(^\d{4} .+$))?     # same as above for group 7
                    you can add more groups if you need

替换：

                    # content of group 1, space, content of group 2
(?3                     # if group 3 exists:
  \n                      # linefeed
                      # content of group 1, space, content of group 3
)                       # end condition
(?4\n )             # same as above fot group 4
(?5\n )             # same as above fot group 5
(?6\n )             # same as above fot group 6
(?7\n )             # same as above fot group 7

截图（之前）：

截图（后）：

Notepad++ 正则表达式将文件中的日期放在每行的开头

Notepad++ regex to put date from file at start of each line

regex

string

notepad++