如何让代码在每个周末执行？

Question

我想每个星期天执行一段代码23:59（晚上11点）（基本上是每个周末）。但是，它应该每周只触发一次。

setInterval() 函数不会在这里删除它，因为应用程序可能会同时重新启动。

如果这无论如何都有帮助，我有这个基本想法：

Set an interval (with setInterval) for every 5-10 seconds and check if it's Sunday and hour 23 (11 pm). However, this solution will be inconsistent and may fire more than once a week. I need a more bullet-proof solution to this.

Answer 1

您可以使用任何 cron 模块（例如 https://www.npmjs.com/package/cron) and set job for 59 23 * * 0 (ranges）

const { CronJob } = require('cron');
const job = new CronJob('59 23 * * 0', mySundayFunc);
job.start();

Answer 2

如何计算开始时的剩余时间，就像这段代码

const WEEK_IN_MS = 604800000;
const ONE_HOUR_IN_MS = 3600000;
const FOUR_DAYS_IN_MS = 4 * WEEK_IN_MS / 7;

function nextInterval() {
    return WEEK_IN_MS - ((Date.now() + FOUR_DAYS_IN_MS) % WEEK_IN_MS) - ONE_HOUR_IN_MS;
}

const interval =  nextInterval();

console.log(`run after ${interval} ms`);

setTimeout(
    () => console.log('Do it!!!'),
    interval
)

如何让代码在每个周末执行？

How to make code execute at each week end?

intervals

node.js