400 Bad Request 使用邮递员复制的请求代码
400 Bad Request using postman copied request code
我已经从
获取了请求代码
OkHttpClient client = new OkHttpClient();
MediaType mediaType = MediaType.parse("application/json");
String json = String.format("{'sex': %s,'age': %d,'evidence': []}", gender, age);
RequestBody body = RequestBody.create(mediaType, json);
Request request = new Request.Builder()
.url("https://api.infermedica.com/covid19/diagnosis")
.post(body)
.addHeader("Content-Type", "application/json")
.addHeader("Accept", "*/*")
.addHeader("App-Id", "XXXXXX")
.addHeader("App-Key", "XXXXXXXXXXXXXXXXXXXXX")
.addHeader("User-Agent", "PostmanRuntime/7.19.0")
.addHeader("Accept", "*/*")
.addHeader("Cache-Control", "no-cache")
.addHeader("Postman-Token", "58fbac21-182b-41e0-bceb-0905d0605858,cd9580e6-f262-4440-ba33-b85877dd087c")
.addHeader("Host", "api.infermedica.com")
.addHeader("Accept-Encoding", "gzip, deflate")
.addHeader("Content-Length", "56")
.addHeader("Connection", "keep-alive")
.addHeader("cache-control", "no-cache")
.build();
com.squareup.okhttp.Response response = client.newCall(request).execute();
我正在尝试提出 post 请求。我已成功 运行 postman 中的请求。我从 postman 那里复制了代码。但是当我 运行 java 中的请求时,我收到 400 Bad Request。我不知道为什么,因为所有 headers 和 body 与 postman.
中的完全相同
您输入的 Sex 中缺少引号
此处确认https://developer.infermedica.com/docs/covid-19
curl "https://api.infermedica.com/covid19/diagnosis" \
-X "POST" \
-H "App-Id: XXXXXXXX" -H "App-Key: XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX" \
-H "Content-Type: application/json" -d '{
"sex": "male",
"age": 30,
"evidence": []
}'
我已经从
获取了请求代码OkHttpClient client = new OkHttpClient();
MediaType mediaType = MediaType.parse("application/json");
String json = String.format("{'sex': %s,'age': %d,'evidence': []}", gender, age);
RequestBody body = RequestBody.create(mediaType, json);
Request request = new Request.Builder()
.url("https://api.infermedica.com/covid19/diagnosis")
.post(body)
.addHeader("Content-Type", "application/json")
.addHeader("Accept", "*/*")
.addHeader("App-Id", "XXXXXX")
.addHeader("App-Key", "XXXXXXXXXXXXXXXXXXXXX")
.addHeader("User-Agent", "PostmanRuntime/7.19.0")
.addHeader("Accept", "*/*")
.addHeader("Cache-Control", "no-cache")
.addHeader("Postman-Token", "58fbac21-182b-41e0-bceb-0905d0605858,cd9580e6-f262-4440-ba33-b85877dd087c")
.addHeader("Host", "api.infermedica.com")
.addHeader("Accept-Encoding", "gzip, deflate")
.addHeader("Content-Length", "56")
.addHeader("Connection", "keep-alive")
.addHeader("cache-control", "no-cache")
.build();
com.squareup.okhttp.Response response = client.newCall(request).execute();
我正在尝试提出 post 请求。我已成功 运行 postman 中的请求。我从 postman 那里复制了代码。但是当我 运行 java 中的请求时,我收到 400 Bad Request。我不知道为什么,因为所有 headers 和 body 与 postman.
中的完全相同您输入的 Sex 中缺少引号
此处确认https://developer.infermedica.com/docs/covid-19
curl "https://api.infermedica.com/covid19/diagnosis" \
-X "POST" \
-H "App-Id: XXXXXXXX" -H "App-Key: XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX" \
-H "Content-Type: application/json" -d '{
"sex": "male",
"age": 30,
"evidence": []
}'