如何从字符串转换或类型转换为 binaryInteger？

Question

"11001001101000000100010101"

"00111000000011010000101011"

和

= 00001000000000000000000001

二进制表示：

"11001001101000000100010101" = > 0b11001001101000000100010101

"00111000000011010000101011" = > 0b00111000000011010000101011

两个字符串，但值看起来像二进制和我想对两个二进制进行按位与运算。

如何将字符串转换为二进制？

Answer 1

UInt 和 String 都有初始化方法，您可以在其中给出数字的基数（基数）

let s1 = "11001001101000000100010101"
let s2 = "00111000000011010000101011"

if let binary1 = UInt(s1, radix: 2), let binary2 = UInt(s2, radix: 2) {
    let res = binary1 & binary2
    print(String(res, radix: 2))
}

输出

1000000000000000000001

如何从字符串转换或类型转换为 binaryInteger？

How to convert or typecast to binaryInteger from string?

binary

bit

ios

swift