SQL select TOP 记录按多列中的几列分区

Question

我要的是所有customer总成本TOP2，所有属性都需要的。),

问题是SQL使用起来太复杂了，有没有办法简化一下？

日期 table 和我的 SQL 如下所示：

area	customer	property	cost
area1	cus1	property11	cost11
area1	cus1	property12	cost12
area1	cus2	property21	cost21

SELECT
    area,
    customer,
    property,
    SUM(cost) AS cost
FROM
    table
WHERE
    customer IN
             (SELECT
                  f.customer
             FROM
                 (SELECT
                      p.area,
                      p.customer,
                      ROW_NUMBER() OVER(PARTITION BY area ORDER BY cost) AS number,
                      p.cost
                 FROM
                    (SELECT
                          area,
                          costomer,
                          SUM(cost) AS cost
                     FROM
                         table
                     GROUP BY
                         costomer
                     )a
                 WHERE number <=2
                 )aa
             )aaa
GROUP BY
    area,
    customer,
    property

Answer 1

您可以使用 ROW_NUMBER() window 函数（或者 RANK() 如果您想要包含关系）：

select t.area, t.customer, t.properties, t.cost
from (
  select area, customer, collect_set(property) properties, sum(cost) cost, 
    row_number() over (partition by area order by sum(cost) desc) rn
  from tablename
  group by area, customer
) t
where t.rn <= 2

SQL select TOP 记录按多列中的几列分区

SQL select TOP records partition by couples of column from multiple columns

sql

group-by

partition