二维动态结构数组无法按预期工作

Question

所以，我有一个二维结构数组。我逐个元素地输入结构，但程序打印了一些随机数据，而不是输入的信息。例如，ptr[0][0].Flat_ID 应该是 101，但它打印出 8，至于其他元素，它完全是胡言乱语。任何想法为什么这样做？结构：

typedef struct
{
   int Flat_ID;
   int count_Rooms;
   int count_Adults;
   int count_Children;
   char Family_Surname[20];
   char Date[15];
   float rent;
}S_Apartament;

而里面的程序main()：

int floors=1, flats_per_floor=2;
S_Apartament Flats;
S_Apartament **ptr = (S_Apartament **)malloc(sizeof(S_Apartament*) * floors);//Declaring an array of pointers. It has to be dynamic, as per the assignment
        if(ptr == NULL)
        {
            printf("Memory fail");
            free(ptr);
            exit(8);

        }
        for (int i = 0; i <  floors; i++)
        {
            ptr[i] = (S_Apartament *)malloc(sizeof(S_Apartament)*flats_per_floor);//Each pointer from the first array now is an array of its own, with elements being structures
            if(ptr[i] == NULL)
            {
                printf("Memory fail");
                free(ptr);
                exit(8);

            }
        }
        for(int i = 0; i <  floors; i++)
        {
            for(int j = 0; j < flats_per_floor; j++)
            {
                printf("ID:\n");
                scanf("%d", &ptr[i][j].Flat_ID);
                printf("\n");
                printf("Rooms:\n");
                scanf("%d", &ptr[i][j].count_Rooms);
                printf("\n");
                printf("Adults:\n");
                scanf("%d", &ptr[i][j].count_Adults);
                printf("\n");
                printf("Children:\n");
                scanf("%d", &ptr[i][j].count_Children);
                printf("\n");
                printf("Name:\n");
                scanf("%s", ptr[i][j].Family_Surname);
                printf("\n");
                printf("Date of entry: \n");
                scanf("%s", ptr[i][j].Date);
                printf("\n");
                printf("Rent:\n");
                scanf("%f", &ptr[i][j].rent);
                printf("\n");
                ptr[i][j]=Flats;
            }
        }
for(int i=0; i< floors; i++)//Prints read information
        {
            for(int j=0; j< flats_per_floor; j++)
            {
                printf("ID: %d\n", ptr[i][j].Flat_ID);
                printf("Rooms: %d\n", ptr[i][j].count_Rooms);
                printf("Adults: %d\n", ptr[i][j].count_Adults);
                printf("Children: %d\n", ptr[i][j].count_Children);
                printf("Name: %s\n", ptr[i][j].Family_Surname);
                printf("Date of entry: %s\n", ptr[i][j].Date);
                printf("Rent: %0.2f\n", ptr[i][j].rent);

            }
            printf("-----------------");
            printf("\n");
        }
free(ptr);

这是一个示例输出： Output

Answer 1

您没有检查 scanf 的结果。只是不成功，没有给成员赋值

Answer 2

命令ptr[i][j]=Flats;将在每次迭代开始时被删除，因为程序没有将信息保存在正确的位置。循环应如下所示：

for(int i = 0; i <  floors; i++)
        {
            for(int j = 0; j < flats_per_floor; j++)
            {
                printf("ID:\n");
                scanf("%d", &ptr[i][j].Flat_ID);
                printf("\n");
                printf("Rooms:\n");
                scanf("%d", &ptr[i][j].count_Rooms);
                printf("\n");
                printf("Adults:\n");
                scanf("%d", &ptr[i][j].count_Adults);
                printf("\n");
                printf("Children:\n");
                scanf("%d", &ptr[i][j].count_Children);
                printf("\n");
                printf("Name:\n");
                scanf("%s", ptr[i][j].Family_Surname);
                printf("\n");
                printf("Date of entry: \n");
                scanf("%s", ptr[i][j].Date);
                printf("\n");
                printf("Rent:\n");
                scanf("%f", &ptr[i][j].rent);
                printf("\n");

            }
        }

二维动态结构数组无法按预期工作

2D dynamic array of structures does not work as intended

c

arrays

pointers

structure

dynamic-memory-allocation